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Reads validated local PYQ JSON files from content/cat/pyqs/validated when uploaded. Predicted papers and reports remain connected from Phase 2A.

Validated PYQs

178

1 local files

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5

22 subtopics

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178

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0

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Arithmetic

99 rows / 8 subtopics

56%

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50 rows / 6 subtopics

28%

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24 rows / 5 subtopics

13%

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4 rows / 2 subtopics

2%

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1 rows / 1 subtopics

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QA2018MCQmedium

A trader sells 10 litres of a mixture of paints A and B, where the amount of B in the mixture does not exceed that of A. The cost of paint A per litre is Rs. 8 more than that of paint B. If the trader sells the entire mixture for Rs. 264 and makes a profit of 10%, then the highest possible cost of paint B, in Rs. per litre, is

A.20
B.16
C.22
D.26
Arithmetic/Mixtures and Alligation/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
A trader sells 10 litres of a mixture of paints A and B, where the amount of B in the mixture does not exceed that of A. The cost of paint A per litre is Rs. 8 more than that of paint B. If the trader sells the entire mixture for Rs. 264 and makes a profit of 10%, then the highest possible cost of paint B, in Rs. per litre, is A)20 B)16 C)22 D)26
QA2018MCQmedium

In a circle with centre O and radius 1 cm, an arc AB makes an angle 60 degrees at O. Let R be the region bounded by the radii OA, OB and the arc AB. If C and D are two points on OA and OB, respectively, such that OC = OD and the area of triangle OCD is half that of R, then the length of OC, in cm, is

A.𝛱 4 1 2
B.𝛱 6 1 2
C.πœ‹ 4 3 1 2
D.𝛱 3 3 1 2
Geometry/Circles/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
In a circle with centre O and radius 1 cm, an arc AB makes an angle 60 degrees at O. Let R be the region bounded by the radii OA, OB and the arc AB. If C and D are two points on OA and OB, respectively, such that OC = OD and the area of triangle OCD is half that of R, then the length of OC, in cm, is A) 𝛱 4 1 2 B) 𝛱 6 1 2 C) πœ‹ 4 3 1 2 D) 𝜫 πŸ‘πŸ‘ 𝟏 𝟐
QA2018TITAeasy

If f(x + 2) = f(x) + f(x + 1) for all positive integers x, and f(11) = 91, f(15) = 617, then f(10) equals. [TITA]

Algebra/Functions/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
If f(x + 2) = f(x) + f(x + 1) for all positive integers x, and f(11) = 91, f(15) = 617, then f(10) equals. [TITA] Answer: 54

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QA2018MCQmedium

The distance from A to B is 60 km. Partha and Narayan start from A at the same time and move towards B. Partha takes four hours more than Narayan to reach B. Moreover, Partha reaches the mid-point of A and B two hours before Narayan reaches B. The speed of Partha, in km per hour, is

A.6
B.3
C.4
D.5
Arithmetic/Time Speed Distance/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
The distance from A to B is 60 km. Partha and Narayan start from A at the same time and move towards B. Partha takes four hours more than Narayan to reach B. Moreover, Partha reaches the mid-point of A and B two hours before Narayan reaches B. The speed of Partha, in km per hour, is A) 6 B) 3 C) 4 D) 5

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QA2018TITAmedium

A CAT aspirant appears for a certain number of tests. His average score increases by 1 if the first 10 tests are not considered, and decreases by 1 if the last 10 tests are not considered. If his average scores for the first 10 and the last 10 tests are 20 and 30, respectively, then the total number of tests taken by him is [TITA]

Arithmetic/Percentages/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
A CAT aspirant appears for a certain number of tests. His average score increases by 1 if the first 10 tests are not considered, and decreases by 1 if the last 10 tests are not considered. If his average scores for the first 10 and the last 10 tests are 20 and 30, respectively, then the total number of tests taken by him is [TITA] Answer: 60

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QA2018MCQmedium

Two types of tea, A and B, are mixed and then sold at Rs. 40 per kg. The profit is 10% if A and B are mixed in the ratio 3: 2, and 5% if this ratio is 2: 3. The cost prices, per kg, of A and B are in the ratio

A.21: 25
B.19: 24
C.18: 25
D.17: 25
Arithmetic/Profit and Loss/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
Two types of tea, A and B, are mixed and then sold at Rs. 40 per kg. The profit is 10% if A and B are mixed in the ratio 3: 2, and 5% if this ratio is 2: 3. The cost prices, per kg, of A and B are in the ratio A) 21: 25 B) 19: 24 C) 18: 25 D) 17: 25

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QA2018MCQhard

A wholesaler bought walnuts and peanuts, the price of walnut per kg being thrice that of peanut per kg. He then sold 8 kg of peanuts at a profit of 10% and 16 kg of walnuts at a profit of 20% to a shopkeeper. However, the shopkeeper lost 5 kg of walnuts and 3 kg of peanuts in transit. He then mixed the remaining nuts and sold the mixture at Rs. 166 per kg, thus making an overall profit of 25%. At what price, in Rs. per kg, did the wholesaler buy the walnuts?

A.84
B.86
C.96
D.98
Arithmetic/Profit and Loss/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
A wholesaler bought walnuts and peanuts, the price of walnut per kg being thrice that of peanut per kg. He then sold 8 kg of peanuts at a profit of 10% and 16 kg of walnuts at a profit of 20% to a shopkeeper. However, the shopkeeper lost 5 kg of walnuts and 3 kg of peanuts in transit. He then mixed the remaining nuts and sold the mixture at Rs. 166 per kg, thus making an overall profit of 25%. At what price, in Rs. per kg, did the wholesaler buy the walnuts? A) 84 B) 86 C) 96 D) 98

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QA2018MCQmedium

When they work alone, B needs 25% more time to finish a job than A does. They two finish the job in 13 days in the following manner: A works alone till half the job is done, then A and B work together for four days, and finally B works alone to complete the remaining 5% of the job. In how many days can B alone finish the entire job?

A.16
B.22
C.20
D.18
Arithmetic/Time and Work/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
When they work alone, B needs 25% more time to finish a job than A does. They two finish the job in 13 days in the following manner: A works alone till half the job is done, then A and B work together for four days, and finally B works alone to complete the remaining 5% of the job. In how many days can B alone finish the entire job? A) 16 B) 22 C) 20 D) 18

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QA2018MCQmedium

Given an equilateral triangle T1 with side 24 cm, a second triangle T2 is formed by joining the midpoints of the sides of T1. Then a third triangle T3 is formed by joining the midpoints of the sides of T2. If this process of forming triangles is continued, the sum of the areas, in sq cm, of infinitely many such triangles T1, T2, T3,... will be

A.192√3
B.164√3
C.248√3
D.188√3
Geometry/Triangles/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
Given an equilateral triangle T1 with side 24 cm, a second triangle T2 is formed by joining the midpoints of the sides of T1. Then a third triangle T3 is formed by joining the midpoints of the sides of T2. If this process of forming triangles is continued, the sum of the areas, in sq cm, of infinitely many such triangles T1, T2, T3,... will be A) 192√3 B)164√3 C)248√3 D)188√3

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QA2018TITAmedium

While multiplying three real numbers, Ashok took one of the numbers as 73 instead of 37. As a result, the product went up by 720. Then the minimum possible value of the sum of squares of the other two numbers is: [TITA]

Arithmetic/Mixtures and Alligation/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
While multiplying three real numbers, Ashok took one of the numbers as 73 instead of 37. As a result, the product went up by 720. Then the minimum possible value of the sum of squares of the other two numbers is: [TITA] Answer: 40

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QA2018MCQeasy

If x is a positive quantity such that 2x =, then x is equal to Answer 3log5 2

A.log5 9
B.1 + log5 3 5
C.1 + log3 5 3
D.log5 8
Algebra/Logarithms/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
If x is a positive quantity such that 2x = 3log 5 2, then x is equal to A) log5 9 B) 𝟏+ π’π’π’ˆπŸ“ πŸ‘ πŸ“ C) 1 + log3 5 3 D) log5 8

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QA2018MCQeasy

If log12 81 = 𝑝, then 3 4βˆ’π‘ 4+𝑝is equal to:

A.log2 8
B.log6 8
C.log4 16
D.log6 16
Algebra/Logarithms/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
If log12 81 = 𝑝, then 3 4βˆ’π‘ 4+𝑝is equal to: A) log2 8 B) π’π’π’ˆπŸ”πŸ– C) log4 16 D) log6 16

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QA2018TITAmedium

A right circular cone, of height 12 ft, stands on its base which has diameter 8 ft. The tip of the cone is cut off with a plane which is parallel to the base and 9 ft from the base. With Ο€ = 22/7, the volume, in cubic ft, of the remaining part of the cone is:[TITA]

Geometry/Mensuration/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
A right circular cone, of height 12 ft, stands on its base which has diameter 8 ft. The tip of the cone is cut off with a plane which is parallel to the base and 9 ft from the base. With Ο€ = 22/7, the volume, in cubic ft, of the remaining part of the cone is:[TITA] Answer: 198

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QA2018TITAmedium

How many numbers with two or more digits can be formed with the digits 1, 2, 3, 4, 5, 6, 7, 8, and 9 so that in every such number, each digit is used at most once and the digits appear in the ascending order?[TITA]

Arithmetic/Mixtures and Alligation/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
How many numbers with two or more digits can be formed with the digits 1, 2, 3, 4, 5, 6, 7, 8, and 9 so that in every such number, each digit is used at most once and the digits appear in the ascending order?[TITA] Answer: 502

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QA2018TITAmedium

John borrowed Rs. 2,10,000 from a bank at an interest rate of 10% per annum, compounded annually. The loan was repaid in two equal instalments, the first after one year and the second after another year. The first instalment was interest of one year plus part of the principal amount, while the second was the rest of the principal amount plus due interest thereon. Then each instalment, in Rs., is: [TITA]

Arithmetic/Simple Interest Compound Interest/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
John borrowed Rs. 2,10,000 from a bank at an interest rate of 10% per annum, compounded annually. The loan was repaid in two equal instalments, the first after one year and the second after another year. The first instalment was interest of one year plus part of the principal amount, while the second was the rest of the principal amount plus due interest thereon. Then each instalment, in Rs., is: [TITA] Answer: 1,21,000

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QA2018MCQeasy

If 𝑒2 + (π‘’βˆ’2π‘£βˆ’1)2= βˆ’4v(u + v), then what is the value of u + 3v?

A.1 4
B.1 2
C.0
D.- 1 4
Arithmetic/Mixtures and Alligation/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
If 𝑒2 + (π‘’βˆ’2π‘£βˆ’1)2= βˆ’4v(u + v), then what is the value of u + 3v? A) 1 4 B) 1 2 C) 0 D) - 𝟏 πŸ’

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QA2018TITAmedium

Point P lies between points A and B such that the length of BP is thrice that of AP. Car 1 starts from A and moves towards B. Simultaneously, car 2 starts from B and moves towards A. Car 2 reaches P one hour after car 1 reaches P. If the speed of car 2 is half that of car 1, then the time, in minutes, taken by car 1 in reaching P from A is:[TITA]

Arithmetic/Time Speed Distance/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
Point P lies between points A and B such that the length of BP is thrice that of AP. Car 1 starts from A and moves towards B. Simultaneously, car 2 starts from B and moves towards A. Car 2 reaches P one hour after car 1 reaches P. If the speed of car 2 is half that of car 1, then the time, in minutes, taken by car 1 in reaching P from A is:[TITA] Answer: 12

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QA2018MCQmedium

Let ABCD be a rectangle inscribed in a circle of radius 13 cm. Which one of the following pairs can represent, in cm, the possible length and breadth of ABCD?

A.25, 10
B.24, 12
C.25, 9
D.24, 10
Geometry/Circles/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
Let ABCD be a rectangle inscribed in a circle of radius 13 cm. Which one of the following pairs can represent, in cm, the possible length and breadth of ABCD? A) 25, 10 B) 24, 12 C) 25, 9 D) 24, 10

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QA2018MCQmedium

In an examination, the maximum possible score is N while the pass mark is 45% of N. A candidate obtains 36 marks, but falls short of the pass mark by 68%. Which one of the following is then correct?

A.N ≀ 200
B.243 ≀ N ≀ 252
C.N β‰₯ 253
D.201 ≀ N ≀ 242
Arithmetic/Percentages/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
In an examination, the maximum possible score is N while the pass mark is 45% of N. A candidate obtains 36 marks, but falls short of the pass mark by 68%. Which one of the following is then correct? A) N ≀ 200 B) 243 ≀ N ≀ 252 C) N β‰₯ 253 D) 201 ≀ N ≀ 242

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QA2018MCQmedium

Let x, y, z be three positive real numbers in a geometric progression such that x < y < z. If 5x, 16y, and 12z are in an arithmetic progression then the common ratio of the geometric progression is

A.1 6
B.3 6
C.3 2
D.5 2
Algebra/Progressions/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
Let x, y, z be three positive real numbers in a geometric progression such that x < y < z. If 5x, 16y, and 12z are in an arithmetic progression then the common ratio of the geometric progression is A) 1 6 B) 3 6 C) 3 2 D) πŸ“ 𝟐

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QA2018TITAeasy

The number of integers x such that 0.25 < 2x < 200, and 2x + 2 is perfectly divisible by either 3 or 4, is [TITA]

Arithmetic/Mixtures and Alligation/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
The number of integers x such that 0.25 < 2x < 200, and 2x + 2 is perfectly divisible by either 3 or 4, is [TITA] Answer: 5

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QA2018TITAmedium

Each of 74 students in a class studies at least one of the three subjects H, E and P. Ten students study all three subjects, while twenty study H and E, but not P. Every student who studies P also studies H or E or both. If the number of students studying H equals that studying E, then the number of students studying H is [TITA]

Arithmetic/Mixtures and Alligation/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
Each of 74 students in a class studies at least one of the three subjects H, E and P. Ten students study all three subjects, while twenty study H and E, but not P. Every student who studies P also studies H or E or both. If the number of students studying H equals that studying E, then the number of students studying H is [TITA] Answer: 52

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QA2018TITAmedium

Train T leaves station X for station Y at 3 pm. Train S, traveling at three quarters of the speed of T, leaves Y for X at 4 pm. The two trains pass each other at a station Z, where the distance between X and Z is three-fifths of that between X and Y. How many hours does train T take for its journey from X to Y? [TITA]

Arithmetic/Time Speed Distance/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
Train T leaves station X for station Y at 3 pm. Train S, traveling at three quarters of the speed of T, leaves Y for X at 4 pm. The two trains pass each other at a station Z, where the distance between X and Z is three-fifths of that between X and Y. How many hours does train T take for its journey from X to Y? [TITA] Answer: 15

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QA2018MCQmedium

Points E, F, G, H lie on the sides AB, BC, CD, and DA, respectively, of a square ABCD. If EFGH is also a square whose area is 62.5% of that of ABCD and CG is longer than EB, then the ratio of length of EB to that of CG is:

A.1: 3
B.4: 9
C.2: 5
D.3: 8
Arithmetic/Profit and Loss/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
Points E, F, G, H lie on the sides AB, BC, CD, and DA, respectively, of a square ABCD. If EFGH is also a square whose area is 62.5% of that of ABCD and CG is longer than EB, then the ratio of length of EB to that of CG is: A) 1: 3 B) 4: 9 C) 2: 5 D) 3: 8

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QA2018MCQeasy

Given that x2018 y2017 = 1/2 and x2016 y2019 = 8, the value of x2 + y3 is

A.37 4
B.31 4
C.35 4
D.33 4
Algebra/Quadratic Equations/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
Given that x2018 y2017 = 1/2 and x2016 y2019 = 8, the value of x2 + y3 is A)37 4 B)31 4 C) 35 4 D)πŸ‘πŸ‘ πŸ’

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QA2018MCQmedium

Raju and Lalitha originally had marbles in the ratio 4: 9. Then Lalitha gave some of her marbles to Raju. As a result, the ratio of the number of marbles with Raju to that with Lalitha became 5: 6. What fraction of her original number of marbles was given by Lalitha to Raju?

A.1 4
B.1 5
C.6 19
D.7 33
Arithmetic/Ratio and Proportion/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
Raju and Lalitha originally had marbles in the ratio 4: 9. Then Lalitha gave some of her marbles to Raju. As a result, the ratio of the number of marbles with Raju to that with Lalitha became 5: 6. What fraction of her original number of marbles was given by Lalitha to Raju? A) 1 4 B) 1 5 C) 6 19 D) πŸ• πŸ‘πŸ‘

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QA2018MCQeasy

If log2(5 + log3a) = 3 and log5(4a + 12 + log2b) = 3, then a + b is equal to:

A.32
B.59
C.67
D.40
Algebra/Linear Equations/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
If log2(5 + log3a) = 3 and log5(4a + 12 + log2b) = 3, then a + b is equal to: A) 32 B) 59 C) 67 D) 40

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QA2018MCQmedium

Humans and robots can both perform a job but at different efficiencies. Fifteen humans and five robots working together take thirty days to finish the job, whereas five humans and fifteen robots working together take sixty days to finish it. How many days will fifteen humans working together (without any robot) take to finish it?

A.40
B.32
C.36
D.45
Arithmetic/Time and Work/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
Humans and robots can both perform a job but at different efficiencies. Fifteen humans and five robots working together take thirty days to finish the job, whereas five humans and fifteen robots working together take sixty days to finish it. How many days will fifteen humans working together (without any robot) take to finish it? A) 40 B) 32 C) 36 D) 45

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QA2018MCQmedium

In a parallelogram ABCD of area 72 sq cm, the sides CD and AD have lengths 9 cm and 16 cm, respectively. Let P be a point on CD such that AP is perpendicular to CD. Then the area, in sq cm, of triangle APD is:

A.18√3
B.24√3
C.32√3
D.12√3
Geometry/Triangles/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
In a parallelogram ABCD of area 72 sq cm, the sides CD and AD have lengths 9 cm and 16 cm, respectively. Let P be a point on CD such that AP is perpendicular to CD. Then the area, in sq cm, of triangle APD is: A) 18√3 B) 24√3 C) 32√3 D) 12√3

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QA2018MCQeasy

In a circle, two parallel chords on the same side of a diameter have lengths 4 cm and 6 cm. If the distance between these chords is 1 cm, then the radius of the circle, in cm, is

A.13
B.14
C.11
D.12
Geometry/Circles/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
In a circle, two parallel chords on the same side of a diameter have lengths 4 cm and 6 cm. If the distance between these chords is 1 cm, then the radius of the circle, in cm, is A) πŸπŸ‘ B) 14 C) 11 D) 12

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QA2018TITAmedium

A tank is fitted with pipes, some filling it and the rest draining it. All filling pipes fill at the same rate, and all draining pipes drain at the same rate. The empty tank gets completely filled in 6 hours when 6 filling and 5 draining pipes are on, but this time becomes 60 hours when 5 filling and 6 draining pipes are on. In how many hours will the empty tank get completely filled when one draining and two filling pipes are on? [TITA]

Arithmetic/Time and Work/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
A tank is fitted with pipes, some filling it and the rest draining it. All filling pipes fill at the same rate, and all draining pipes drain at the same rate. The empty tank gets completely filled in 6 hours when 6 filling and 5 draining pipes are on, but this time becomes 60 hours when 5 filling and 6 draining pipes are on. In how many hours will the empty tank get completely filled when one draining and two filling pipes are on? [TITA] Answer: 10

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QA2018MCQeasy

If among 200 students, 105 like pizza and 134 like burger, then the number of students who like only burger can possibly be

A.26
B.23
C.96
D.93
Arithmetic/Mixtures and Alligation/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
If among 200 students, 105 like pizza and 134 like burger, then the number of students who like only burger can possibly be A) 26 B) 23 C) 96 D) 93

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QA2018TITAmedium

Let f(x)=min{2x2, 52 - 5x}, where x is any positive real number. Then the maximum possible value of f(x) is [TITA]

Algebra/Functions/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
Let f(x)=min{2x2, 52 - 5x}, where x is any positive real number. Then the maximum possible value of f(x) is [TITA] Answer: 32

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QA2018MCQhard

In an apartment complex, the number of people aged 51 years and above is 30 and there are at most 39 people whose ages are below 51 years. The average age of all the people in the apartment complex is 38 years. What is the largest possible average age, in years, of the people whose ages are below 51 years?

A.25
B.26
C.27
D.28
Arithmetic/Ratio and Proportion/data/extracted_text/2018/Slot_1/QA/CAT_2018_Slot_1_QA.txt
In an apartment complex, the number of people aged 51 years and above is 30 and there are at most 39 people whose ages are below 51 years. The average age of all the people in the apartment complex is 38 years. What is the largest possible average age, in years, of the people whose ages are below 51 years? A)25 B)26 C)27 D)28

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QA2018MCQhard

Points A, P, Q and B lie on the same line such that P, Q and B are, respectively, 100 km, 200 km and 300 km away from A. Cars 1 and 2 leave A at the same time and move towards B. Simultaneously, car 3 leaves B and moves towards A. Car 3 meets Car 1 at Q, and Car 2 at P. If each car is moving in uniform speed then the ratio of the speed of Car 2 to that of Car 1 is

A.1: 4
B.2: 9
C.1: 2
D.2: 7
Arithmetic/Time Speed Distance/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
Points A, P, Q and B lie on the same line such that P, Q and B are, respectively, 100 km, 200 km and 300 km away from A. Cars 1 and 2 leave A at the same time and move towards B. Simultaneously, car 3 leaves B and moves towards A. Car 3 meets Car 1 at Q, and Car 2 at P. If each car is moving in uniform speed then the ratio of the speed of Car 2 to that of Car 1 is A) 1: 4 B) 2: 9 C) 1: 2 D) 2: 7

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QA2018MCQmedium

Let π‘Ž1, π‘Ž2, π‘Ž3,...,π‘Ž52 be positive integers such that π‘Ž1 οΌœπ‘Ž2 <... οΌœπ‘Ž52. Suppose, their arithmetic mean is one less than the arithmetic mean of π‘Ž2, π‘Ž3,..., π‘Ž52. If π‘Ž52 = 100, then the largest possible value of π‘Ž1 is

A.48
B.20
C.45
D.23
Arithmetic/Averages/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
Let π‘Ž1, π‘Ž2, π‘Ž3,...,π‘Ž52 be positive integers such that π‘Ž1 οΌœπ‘Ž2 <... οΌœπ‘Ž52. Suppose, their arithmetic mean is one less than the arithmetic mean of π‘Ž2, π‘Ž3,..., π‘Ž52. If π‘Ž52 = 100, then the largest possible value of π‘Ž1 is A) 48 B) 20 C) 45 D) 23

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QA2018MCQmedium

There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18: 7. The mixtures from drums 1 and 2 are mixed in the ratio 3: 4 and in this final mixture, A and B are in the ratio 13: 7. In drum 2, then A and B were in the ratio

A.251: 163
B.239: 161
C.220: 149
D.229: 141
Arithmetic/Mixtures and Alligation/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18: 7. The mixtures from drums 1 and 2 are mixed in the ratio 3: 4 and in this final mixture, A and B are in the ratio 13: 7. In drum 2, then A and B were in the ratio A) 251: 163 B) 239: 161 C) 220: 149 D) 229: 141

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QA2018TITAmedium

On a triangle ABC, a circle with diameter BC is drawn, intersecting AB and AC at points P and Q, respectively. If the lengths of AB, AC, and CP are 30 cm, 25 cm, and 20 cm respectively, then the length of BQ, in cm, is (TITA)

Arithmetic/Profit and Loss/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
On a triangle ABC, a circle with diameter BC is drawn, intersecting AB and AC at points P and Q, respectively. If the lengths of AB, AC, and CP are 30 cm, 25 cm, and 20 cm respectively, then the length of BQ, in cm, is (TITA) Answer: 24

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QA2018TITAeasy

Let t1, t2,… be real numbers such that t1+ t2 +... + tn = 2n2 + 9n + 13, for every positive integer n β‰₯ 2. If tk=103, then k equals (TITA)

Arithmetic/Mixtures and Alligation/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
Let t1, t2,… be real numbers such that t1+ t2 +... + tn = 2n2 + 9n + 13, for every positive integer n β‰₯ 2. If tk=103, then k equals (TITA) Answer: 24

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QA2018MCQeasy

From a rectangle ABCD of area 768 sq cm, a semicircular part with diameter AB and area 72Ο€ sq cm is removed. The perimeter of the leftover portion, in cm, is

A.88 + 12Ο€
B.80 + 16Ο€
C.86 + 8Ο€
D.82 + 24Ο€
Arithmetic/Mixtures and Alligation/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
From a rectangle ABCD of area 768 sq cm, a semicircular part with diameter AB and area 72Ο€ sq cm is removed. The perimeter of the leftover portion, in cm, is A) 88 + 12Ο€ B) 80 + 16Ο€ C) 86 + 8Ο€ D) 82 + 24Ο€

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QA2018TITAmedium

If N and x are positive integers such that NN = 2160 and N2 + 2N is an integral multiple of 2x, then the largest possible x is (TITA)

Arithmetic/Mixtures and Alligation/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
If N and x are positive integers such that NN = 2160 and N2 + 2N is an integral multiple of 2x, then the largest possible x is (TITA) Answer: 10

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QA2018MCQeasy

A chord of length 5 cm subtends an angle of 60Β° at the centre of a circle. The length, in cm, of a chord that subtends an angle of 120Β° at the centre of the same circle is

A.2Ο€
B.5√3
C.6√2
D.8
Geometry/Circles/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
A chord of length 5 cm subtends an angle of 60Β° at the centre of a circle. The length, in cm, of a chord that subtends an angle of 120Β° at the centre of the same circle is A) 2Ο€ B) 5√3 C) 6√2 D) 8

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QA2018MCQeasy

If 𝑝3 = π‘ž4 = π‘Ÿ5 = 𝑠6, then the value of logπ‘†π‘π‘žπ‘Ÿis equal to

A.24 5
B.1
C.47 10
D.16 5
Arithmetic/Mixtures and Alligation/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
If 𝑝3 = π‘ž4 = π‘Ÿ5 = 𝑠6, then the value of logπ‘†π‘π‘žπ‘Ÿis equal to A) 24 5 B) 1 C) πŸ’πŸ• 𝟏𝟎 D) 16 5

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QA2018TITAmedium

In a tournament, there are 43 junior level and 51 senior level participants. Each pair of juniors play one match. Each pair of seniors play one match. There is no junior versus senior match. The number of girl versus girl matches in junior level is 153, while the number of boy versus boy matches in senior level is 276. The number of matches a boy plays against a girl is (TITA)

Arithmetic/Time and Work/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
In a tournament, there are 43 junior level and 51 senior level participants. Each pair of juniors play one match. Each pair of seniors play one match. There is no junior versus senior match. The number of girl versus girl matches in junior level is 153, while the number of boy versus boy matches in senior level is 276. The number of matches a boy plays against a girl is (TITA) Answer: 1098

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QA2018MCQmedium

A 20% ethanol solution is mixed with another ethanol solution, say, S of unknown concentration in the proportion 1:3 by volume. This mixture is then mixed with an equal volume of 20% ethanol solution. If the resultant mixture is a 31.25% ethanol solution, then the unknown concentration of S is

A.50%
B.55%
C.48%
D.52%
Arithmetic/Mixtures and Alligation/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
A 20% ethanol solution is mixed with another ethanol solution, say, S of unknown concentration in the proportion 1:3 by volume. This mixture is then mixed with an equal volume of 20% ethanol solution. If the resultant mixture is a 31.25% ethanol solution, then the unknown concentration of S is A) 50% B) 55% C) 48% D) 52%

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QA2018MCQeasy

The area of a rectangle and the square of its perimeter are in the ratio 1: 25. Then the lengths of the shorter and longer sides of the rectangle are in the ratio:

A.3: 8
B.2: 9
C.1: 4
D.1: 3
Geometry/Triangles/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
The area of a rectangle and the square of its perimeter are in the ratio 1: 25. Then the lengths of the shorter and longer sides of the rectangle are in the ratio: A) 3: 8 B) 2: 9 C) 1: 4 D) 1: 3

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QA2018MCQeasy

The smallest integer n for which 4n > 1719 holds, is closest to

A.33
B.39
C.37
D.35
Arithmetic/Mixtures and Alligation/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
The smallest integer n for which 4n >1719 holds, is closest to A) 33 B) 39 C) 37 D) 35

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QA2018TITAeasy

The smallest integer n such that 𝑛3 βˆ’11𝑛2 + 32π‘›βˆ’28 > 0 is (TITA)

Arithmetic/Mixtures and Alligation/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
The smallest integer n such that 𝑛3 βˆ’11𝑛2 + 32π‘›βˆ’28 > 0 is (TITA) Answer: 8

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QA2018MCQeasy

A parallelogram ABCD has area 48 sqcm. If the length of CD is 8 cm and that of AD is s cm, then which one of the following is necessarily true?

A.s β‰₯ 6
B.s β‰  6
C.5 ≀ s ≀ 7
D.s ≀ 6
Arithmetic/Mixtures and Alligation/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
A parallelogram ABCD has area 48 sqcm. If the length of CD is 8 cm and that of AD is s cm, then which one of the following is necessarily true? A) s β‰₯ 6 B) s β‰  6 C) 5 ≀ s ≀ 7 D) s ≀ 6

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QA2018MCQeasy

The value of the sum 7 x 11 + 11 x 15 + 15 x 19 +..... + 95 x 99 is

A.80707
B.80751
C.80730
D.80773
Arithmetic/Mixtures and Alligation/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
The value of the sum 7 x 11 + 11 x 15 + 15 x 19 +..... + 95 x 99 is A) 80707 B) 80751 C) 80730 D) 80773

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QA2018TITAmedium

On a long stretch of east-west road, A and B are two points such that B is 350 km west of A. One car starts from A and another from B at the same time. If they move towards each other, then they meet after 1 hour. If they both move towards east, then they meet in 7 hrs. The difference between their speeds, in km per hour, is (TITA)

Arithmetic/Time Speed Distance/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
On a long stretch of east-west road, A and B are two points such that B is 350 km west of A. One car starts from A and another from B at the same time. If they move towards each other, then they meet after 1 hour. If they both move towards east, then they meet in 7 hrs. The difference between their speeds, in km per hour, is (TITA) Answer: 50

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QA2018MCQeasy

If the sum of squares of two numbers is 97, then which one of the following cannot be their product?

A.64
B.-32
C.16
D.48
Arithmetic/Mixtures and Alligation/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
If the sum of squares of two numbers is 97, then which one of the following cannot be their product? A) 64 B) -32 C) 16 D) 48

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QA2018MCQmedium

A jar contains a mixture of 175 ml water and 700 ml alcohol. Gopal takes out 10% of the mixture and substitutes it by water of the same amount. The process is repeated once again. The percentage of water in the mixture is now

A.25.4
B.20.5
C.30.3
D.35.2
Arithmetic/Mixtures and Alligation/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
A jar contains a mixture of 175 ml water and 700 ml alcohol. Gopal takes out 10% of the mixture and substitutes it by water of the same amount. The process is repeated once again. The percentage of water in the mixture is now A) 25.4 B) 20.5 C) 30.3 D) 35.2

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QA2018TITAmedium

Points A and B are 150 km apart. Cars 1 and 2 travel from A to B, but car 2 starts from A when car 1 is already 20 km away from A. Each car travels at a speed of 100 kmph for the first 50 km, at 50 kmph for the next 50 km, and at 25 kmph for the last 50 km. The distance, in km, between car 2 and B when car 1 reaches B is (TITA)

Arithmetic/Time Speed Distance/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
Points A and B are 150 km apart. Cars 1 and 2 travel from A to B, but car 2 starts from A when car 1 is already 20 km away from A. Each car travels at a speed of 100 kmph for the first 50 km, at 50 kmph for the next 50 km, and at 25 kmph for the last 50 km. The distance, in km, between car 2 and B when car 1 reaches B is (TITA) Answer: 5

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QA2018MCQhard

A tank is emptied everyday at a fixed time point. Immediately thereafter, either pump A or pump B or both start working until the tank is full. On Monday, A alone completed filling the tank at 8 pm. On Tuesday, B alone completed filling the tank at 6 pm. On Wednesday, A alone worked till 5 pm, and then B worked alone from 5 pm to 7 pm, to fill the tank. At what time was the tank filled on Thursday if both pumps were used simultaneously all along?

A.4: 12 PM
B.4: 24 PM
C.4: 48 PM
D.4: 36 PM
Arithmetic/Time and Work/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
A tank is emptied everyday at a fixed time point. Immediately thereafter, either pump A or pump B or both start working until the tank is full. On Monday, A alone completed filling the tank at 8 pm. On Tuesday, B alone completed filling the tank at 6 pm. On Wednesday, A alone worked till 5 pm, and then B worked alone from 5 pm to 7 pm, to fill the tank. At what time was the tank filled on Thursday if both pumps were used simultaneously all along? A) 4: 12 PM B) 4: 24 PM C) 4: 48 PM D) 4: 36 PM

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QA2018MCQmedium

Ramesh and Ganesh can together complete a work in 16 days. After seven days of working together, Ramesh got sick and his efficiency fell by 30%. As a result, they completed the work in 17 days instead of 16 days. If Ganesh had worked alone after Ramesh got sick, in how many days would he have completed the remaining work?

A.12
B.14.5
C.13.5
D.11
Arithmetic/Time and Work/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
Ramesh and Ganesh can together complete a work in 16 days. After seven days of working together, Ramesh got sick and his efficiency fell by 30%. As a result, they completed the work in 17 days instead of 16 days. If Ganesh had worked alone after Ramesh got sick, in how many days would he have completed the remaining work? A) 12 B) 14.5 C) 13.5 D) 11

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QA2018TITAmedium

If a and b are integers such that 2x2 βˆ’ ax + 2 > 0 and x2 βˆ’ bx + 8 β‰₯ 0 for all real numbers x, then the largest possible value of 2a βˆ’ 6b is (TITA)

Algebra/Quadratic Equations/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
If a and b are integers such that 2x2 βˆ’ ax + 2 > 0 and x2 βˆ’ bx + 8 β‰₯ 0 for all real numbers x, then the largest possible value of 2a βˆ’ 6b is (TITA) Answer: 36

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QA2018MCQmedium

The scores of Amal and Bimal in an examination are in the ratio 11: 14. After an appeal, their scores increase by the same amount and their new scores are in the ratio 47: 56. The ratio of Bimal’s new score to that of his original score is

A.3: 2
B.4: 3
C.5: 4
D.8: 5
Arithmetic/Percentages/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
The scores of Amal and Bimal in an examination are in the ratio 11: 14. After an appeal, their scores increase by the same amount and their new scores are in the ratio 47: 56. The ratio of Bimal’s new score to that of his original score is A) 3: 2 B) 4: 3 C) 5: 4 D) 8: 5

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QA2018MCQeasy

A triangle ABC has area 32 sq units and its side BC, of length 8 units, lies on the line x = 4. Then the shortest possible distance between A and the point (0,0) is

A.4√2 units
B.2√2 units
C.4 units
D.8 units
Geometry/Triangles/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
A triangle ABC has area 32 sq units and its side BC, of length 8 units, lies on the line x = 4. Then the shortest possible distance between A and the point (0,0) is A) 4√2 units B) 2√2 units C) 4 units D) 8 units

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QA2018MCQeasy

How many two-digit numbers, with a non-zero digit in the units place, are there which are more than thrice the number formed by interchanging the positions of its digits?

A.5
B.8
C.7
D.6
Number System/Digits/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
How many two-digit numbers, with a non-zero digit in the units place, are there which are more than thrice the number formed by interchanging the positions of its digits? A) 5 B) 8 C) 7 D) 6

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QA2018TITAhard

A water tank has inlets of two types A and B. All inlets of type A when open, bring in water at the same rate. All inlets of type B, when open, bring in water at the same rate. The empty tank is completely filled in 30 minutes if 10 inlets of type A and 45 inlets of type B are open, and in 1 hour if 8 inlets of type A and 18 inlets of type B are open. In how many minutes will the empty tank get completely filled if 7 inlets of type A and 27 inlets of type B are open? (TITA)

Arithmetic/Time and Work/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
A water tank has inlets of two types A and B. All inlets of type A when open, bring in water at the same rate. All inlets of type B, when open, bring in water at the same rate. The empty tank is completely filled in 30 minutes if 10 inlets of type A and 45 inlets of type B are open, and in 1 hour if 8 inlets of type A and 18 inlets of type B are open. In how many minutes will the empty tank get completely filled if 7 inlets of type A and 27 inlets of type B are open? (TITA) Answer: 48

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QA2018TITAhard

Gopal borrows Rs. X from Ankit at 8% annual interest. He then adds Rs. Y of his own money and lends Rs. X+Y to Ishan at 10% annual interest. At the end of the year, after returning Ankit’s dues, the net interest retained by Gopal is the same as that accrued to Ankit. On the other hand, had Gopal lent Rs. X+2Y to Ishan at 10%, then the net interest retained by him would have increased by Rs. 150. If all interests are compounded annually, then find the value of X + Y. (TITA)

Arithmetic/Simple Interest Compound Interest/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
Gopal borrows Rs. X from Ankit at 8% annual interest. He then adds Rs. Y of his own money and lends Rs. X+Y to Ishan at 10% annual interest. At the end of the year, after returning Ankit’s dues, the net interest retained by Gopal is the same as that accrued to Ankit. On the other hand, had Gopal lent Rs. X+2Y to Ishan at 10%, then the net interest retained by him would have increased by Rs. 150. If all interests are compounded annually, then find the value of X + Y. (TITA) Answer: 4000

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QA2018TITAmedium

The arithmetic mean of x, y and z is 80, and that of x, y, z, u and v is 75, where u = (x+y)/2 and v = (y+z)/2. If x β‰₯ z, then the minimum possible value of x is (TITA)

Algebra/Linear Equations/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
The arithmetic mean of x, y and z is 80, and that of x, y, z, u and v is 75, where u = (x+y)/2 and v = (y+z)/2. If x β‰₯ z, then the minimum possible value of x is (TITA) Answer: 105

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QA2018TITAmedium

Let f(x)=max{5x, 52 - 2x2}, where x is any positive real number. Then the minimum possible value of f(x) is (TITA)

Algebra/Functions/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
Let f(x)=max{5x, 52 - 2x2}, where x is any positive real number. Then the minimum possible value of f(x) is (TITA) Answer: -65/2

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QA2018MCQmedium

For two sets A and B, let AΞ”B denote the set of elements which belong to A or B but not both. If P = {1,2,3,4}, Q = {2,3,5,6,}, R = {1,3,7,8,9}, S = {2,4,9,10}, then the number of elements in (PΞ”Q)Ξ”(RΞ”S) is

A.7
B.8
C.9
D.6
Arithmetic/Time and Work/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
For two sets A and B, let AΞ”B denote the set of elements which belong to A or B but not both. If P = {1,2,3,4}, Q = {2,3,5,6,}, R = {1,3,7,8,9}, S = {2,4,9,10}, then the number of elements in (PΞ”Q)Ξ”(RΞ”S) is A) 7 B) 8 C) 9 D) 6

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QA2018MCQmedium

If A = {62n - 35n - 1: n = 1,2,3,...} and B = {35(n-1): n = 1,2,3,...} then which of the following is true?

A.Neither every member of A is in B nor every member of B is in A
B.Every member of A is in B and at least one member of B is not in A
C.Every member of B is in
D.At least one member of A is not in B
Arithmetic/Mixtures and Alligation/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
If A = {62n - 35n - 1: n = 1,2,3,...} and B = {35(n-1): n = 1,2,3,...} then which of the following is true? A) Neither every member of A is in B nor every member of B is in A B) Every member of A is in B and at least one member of B is not in A C) Every member of B is in A. D) At least one member of A is not in B

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QA2018MCQhard

The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. If three salt solutions A, B, C are mixed in the proportion 1: 2: 3, then the resulting solution has strength 20%. If instead the proportion is 3: 2: 1, then the resulting solution has strength 30%. A fourth solution, D, is produced by mixing B and C in the ratio 2: 7. The ratio of the strength of D to that of A is

A.3: 10
B.1: 3
C.2: 5
D.1: 4
Arithmetic/Ratio and Proportion/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. If three salt solutions A, B, C are mixed in the proportion 1: 2: 3, then the resulting solution has strength 20%. If instead the proportion is 3: 2: 1, then the resulting solution has strength 30%. A fourth solution, D, is produced by mixing B and C in the ratio 2: 7. The ratio of the strength of D to that of A is A) 3: 10 B) 1: 3 C) 2: 5 D) 1: 4

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QA2018MCQhard

1 log2 100 βˆ’ 1 log4 100 + 1 log5 100 βˆ’ 1 log10 100 + 1 log20 100 βˆ’ 1 log25 100 + 1 log50 100

A.0
B.1 2
C.-4
D.10
Arithmetic/Ratio and Proportion/data/extracted_text/2018/Slot_2/QA/CAT_2018_Slot_2_QA.txt
1 log2 100 βˆ’ 1 log4 100 + 1 log5 100 βˆ’ 1 log10 100 + 1 log20 100 βˆ’ 1 log25 100 + 1 log50 100 A) 0 B)𝟏 𝟐 C) -4 D) 10

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QA2019TITAmedium

In a class, 60% of the students are girls and the rest are boys. There are 30 more girls than boys. If 68% of the students, including 30 boys, pass an examination, the percentage of the girls who do not pass is [TITA]

Arithmetic/Percentages/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
In a class, 60% of the students are girls and the rest are boys. There are 30 more girls than boys. If 68% of the students, including 30 boys, pass an examination, the percentage of the girls who do not pass is [TITA] Answer: 20

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QA2019MCQeasy

If (5.55)x = (0.555)y = 1000, then the value of 1 π‘₯βˆ’1 𝑦is

A.1
B.1 3
C.2 3
D.3
Algebra/Progressions/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
If (5.55)x = (0.555)y= 1000, then the value of 1 π‘₯βˆ’1 𝑦is A) 1 B) 𝟏 πŸ‘ C) 2 3 D) 3

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QA2019TITAeasy

With rectangular axes of coordinates, the number of paths from (1,1) to (8,10) via (4,6), where each step from any point (x, y) is either to (x, y+1) or to (x+1, y), is [TITA]

Geometry/Coordinate Geometry/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
With rectangular axes of coordinates, the number of paths from (1,1) to (8,10) via (4,6), where each step from any point (x, y) is either to (x, y+1) or to (x+1, y), is [TITA] Answer: 3920

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QA2019MCQmedium

A club has 256 members of whom 144 can play football, 123 can play tennis, and 132 can play cricket. Moreover, 58 members can play both football and tennis, 25 can play both cricket and tennis, while 63 can play both football and cricket. If every member can play at least one game, then the number of members who can play only tennis is

A.32
B.43
C.38
D.45
Algebra/Inequalities/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
A club has 256 members of whom 144 can play football, 123 can play tennis, and 132 can play cricket. Moreover, 58 members can play both football and tennis, 25 can play both cricket and tennis, while 63 can play both football and cricket. If every member can play at least one game, then the number of members who can play only tennis is A) 32 B) 43 C) 38 D) 45

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QA2019MCQmedium

In a circle of radius 11 cm, CD is a diameter and AB is a chord of length 20.5 cm. If AB and CD intersect at a point E inside the circle and CE has length 7 cm, then the difference of the lengths of BE and AE, in cm, is

A.1.5
B.3.5
C.0.5
D.2.5
Geometry/Circles/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
In a circle of radius 11 cm, CD is a diameter and AB is a chord of length 20.5 cm. If AB and CD intersect at a point E inside the circle and CE has length 7 cm, then the difference of the lengths of BE and AE, in cm, is A) 1.5 B) 3.5 C) 0.5 D) 2.5

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QA2019MCQmedium

Meena scores 40% in an examination and after review, even though her score is increased by 50%, she fails by 35 marks. If her post- review score is increased by 20%, she will have 7 marks more than the passing score. The percentage score needed for passing the examination is

A.75
B.80
C.60
D.70
Arithmetic/Percentages/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
Meena scores 40% in an examination and after review, even though her score is increased by 50%, she fails by 35 marks. If her post-review score is increased by 20%, she will have 7 marks more than the passing score. The percentage score needed for passing the examination is A) 75 B) 80 C) 60 D) 70

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QA2019MCQmedium

Corners are cut off from an equilateral triangle T to produce a regular hexagon H. Then, the ratio of the area of H to the area of T is

A.5: 6
B.3: 4
C.2: 3
D.4: 5
Geometry/Triangles/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
Corners are cut off from an equilateral triangle T to produce a regular hexagon H. Then, the ratio of the area of H to the area of T is A) 5: 6 B) 3: 4 C) 2: 3 D) 4: 5

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QA2019TITAmedium

Let T be the triangle formed by the straight line 3x + 5y - 45 = 0 and the coordinate axes. Let the circumcircle of T have radius of length L, measured in the same unit as the coordinate axes. Then, the integer closest to L is [TITA]

Geometry/Triangles/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
Let T be the triangle formed by the straight line 3x + 5y - 45 = 0 and the coordinate axes. Let the circumcircle of T have radius of length L, measured in the same unit as the coordinate axes. Then, the integer closest to L is [TITA] Answer: 9

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QA2019TITAmedium

For any positive integer n, let f(n) = n(n + 1) if n is even, and f(n) = n + 3 if n is odd. If m is a positive integer such that 8f(m + 1) - f(m) = 2, then m equals [TITA]

Algebra/Functions/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
For any positive integer n, let f(n) = n(n + 1) if n is even, and f(n) = n + 3 if n is odd. If m is a positive integer such that 8f(m + 1) - f(m) = 2, then m equals [TITA] Answer: 10

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QA2019MCQmedium

If the population of a town is p in the beginning of any year then it becomes 3+2p in the beginning of the next year. If the population in the beginning of 2019 is 1000, then the population in the beginning of 2034 will be

A.(1003)15 + 6
B.(997)15 - 3
C.(1003)215 - 3
D.(997)214 + 3
Algebra/Progressions/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
If the population of a town is p in the beginning of any year then it becomes 3+2p in the beginning of the next year. If the population in the beginning of 2019 is 1000, then the population in the beginning of 2034 will be A) (1003)15 + 6 B) (997)15 - 3 C) (1003)215 - 3 D) (997)214 + 3

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QA2019TITAmedium

A person invested a total amount of Rs 15 lakh. A part of it was invested in a fixed deposit earning 6% annual interest, and the remaining amount was invested in two other deposits in the ratio 2: 1, earning annual interest at the rates of 4% and 3%, respectively. If the total annual interest income is Rs 76000 then the amount (in Rs lakh) invested in the fixed deposit was [TITA]

Arithmetic/Simple Interest Compound Interest/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
A person invested a total amount of Rs 15 lakh. A part of it was invested in a fixed deposit earning 6% annual interest, and the remaining amount was invested in two other deposits in the ratio 2: 1, earning annual interest at the rates of 4% and 3%, respectively. If the total annual interest income is Rs 76000 then the amount (in Rs lakh) invested in the fixed deposit was [TITA] Answer: 9

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QA2019MCQmedium

The product of two positive numbers is 616. If the ratio of the difference of their cubes to the cube of their difference is 157:3, then the sum of the two numbers is

A.50
B.85
C.95
D.58
Arithmetic/Ratio and Proportion/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
The product of two positive numbers is 616. If the ratio of the difference of their cubes to the cube of their difference is 157:3, then the sum of the two numbers is A) 50 B) 85 C) 95 D) 58

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QA2019MCQmedium

On selling a pen at 5% loss and a book at 15% gain, Karim gains Rs. 7. If he sells the pen at 5% gain and the book at 10% gain, he gains Rs. 13. What is the cost price of the book in Rupees?

A.80
B.85
C.100
D.95
Arithmetic/Profit and Loss/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
On selling a pen at 5% loss and a book at 15% gain, Karim gains Rs. 7. If he sells the pen at 5% gain and the book at 10% gain, he gains Rs. 13. What is the cost price of the book in Rupees? A) 80 B) 85 C) 100 D) 95

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QA2019MCQmedium

Two cars travel the same distance starting at 10:00 am and 11:00 am, respectively, on the same day. They reach their common destination at the same point of time. If the first car travelled for at least 6 hours, then the highest possible value of the percentage by which the speed of the second car could exceed that of the first car is

A.20
B.10
C.30
D.25
Arithmetic/Time Speed Distance/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
Two cars travel the same distance starting at 10:00 am and 11:00 am, respectively, on the same day. They reach their common destination at the same point of time. If the first car travelled for at least 6 hours, then the highest possible value of the percentage by which the speed of the second car could exceed that of the first car is A) 20 B) 10 C) 30 D) 25

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QA2019MCQmedium

At their usual efficiency levels, A and B together finish a task in 12 days. If A had worked half as efficiently as she usually does, and B had worked thrice as efficiently as he usually does, the task would have been completed in 9 days. How many days would A take to finish the task if she works alone at her usual efficiency?

A.18
B.12
C.24
D.36
Arithmetic/Time and Work/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
At their usual efficiency levels, A and B together finish a task in 12 days. If A had worked half as efficiently as she usually does, and B had worked thrice as efficiently as he usually does, the task would have been completed in 9 days. How many days would A take to finish the task if she works alone at her usual efficiency? A) 18 B) 12 C) 24 D) 36

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QA2019TITAeasy

If a1 + a2 + a3 + …. + an = 3(2n+1 - 2), for every n ο‚³1, then a11 equals [TITA]

Algebra/Progressions/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
If a1 + a2 + a3 + …. + an= 3(2n+1 - 2), for every n ο‚³1, then a11 equals [TITA] Answer: 6144

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QA2019MCQeasy

The number of the real roots of the equation 2cos (x ( x + 1 ) ) = 2x + 2-x is

A.0
B.Infinite
C.1
D.2
Algebra/Quadratic Equations/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
The number of the real roots of the equation 2cos (x ( x + 1 ) ) = 2x + 2-x is A) 0 B) Infinite C) 1 D) 2

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QA2019MCQmedium

The income of Amala is 20% more than that of Bimala and 20% less than that of Kamala. If Kamala's income goes down by 4% and Bimala's goes up by 10%, then the percentage by which Kamala's income would exceed Bimala's is nearest to

A.28
B.29
C.31
D.32
Arithmetic/Percentages/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
The income of Amala is 20% more than that of Bimala and 20% less than that of Kamala. If Kamala's income goes down by 4% and Bimala's goes up by 10%, then the percentage by which Kamala's income would exceed Bimala's is nearest to A) 28 B) 29 C) 31 D) 32

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QA2019TITAmedium

In a race of three horses, the first beat the second by 11 metres and the third by 90 metres. If the second beat the third by 80 metres, what was the length, in metres, of the racecourse? [TITA]

Arithmetic/Time Speed Distance/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
In a race of three horses, the first beat the second by 11 metres and the third by 90 metres. If the second beat the third by 80 metres, what was the length, in metres, of the racecourse? [TITA] Answer: 880

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QA2019MCQeasy

If a1, a2, ….. are in A.P, then, 1 π‘Ž1 + π‘Ž2 + 1 π‘Ž2 + π‘Ž3 + …… + 1 π‘Žπ‘›+ π‘Žπ‘›+1 is equal to

A.𝑛 π‘Ž1 + π‘Žπ‘›+1
B.π‘›βˆ’1 π‘Ž1 + π‘Žπ‘›
C.𝑛 π‘Ž1 βˆ’π‘Žπ‘›+1
D.π‘›βˆ’1 π‘Ž1 + π‘Žπ‘›βˆ’1
Algebra/Progressions/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
If a1, a2, ….. are in A.P, then, 1 π‘Ž1 + π‘Ž2 + 1 π‘Ž2 + π‘Ž3 + …… + 1 π‘Žπ‘›+ π‘Žπ‘›+1 is equal to A) 𝒏 π’‚πŸ+ 𝒂𝒏+𝟏 B) π‘›βˆ’1 π‘Ž1 + π‘Žπ‘› C) 𝑛 π‘Ž1 βˆ’π‘Žπ‘›+1 D) π‘›βˆ’1 π‘Ž1 + π‘Žπ‘›βˆ’1

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QA2019MCQmedium

AB is a diameter of a circle of radius 5 cm. Let P and Q be two points on the circle so that the length of PB is 6 cm, and the length of AP is twice that of AQ. Then the length, in cm, of QB is nearest to

A.8.5
B.9.3
C.9.1
D.7.8
Geometry/Circles/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
AB is a diameter of a circle of radius 5 cm. Let P and Q be two points on the circle so that the length of PB is 6 cm, and the length of AP is twice that of AQ. Then the length, in cm, of QB is nearest to A) 8.5 B) 9.3 C) 9.1 D) 7.8

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QA2019MCQmedium

One can use three different transports which move at 10, 20, and 30 kmph, respectively. To reach from A to B, Amal took each mode of transport 1/3 of his total journey time, while Bimal took each mode of transport 1/3 of the total distance. The percentage by which Bimal’s travel time exceeds Amal’s travel time is nearest to

A.22
B.19
C.21
D.20
Arithmetic/Time Speed Distance/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
One can use three different transports which move at 10, 20, and 30 kmph, respectively. To reach from A to B, Amal took each mode of transport 1/3 of his total journey time, while Bimal took each mode of transport 1/3 of the total distance. The percentage by which Bimal’s travel time exceeds Amal’s travel time is nearest to A) 22 B) 19 C) 21 D) 20

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QA2019MCQmedium

Amala, Bina, and Gouri invest money in the ratio 3: 4: 5 in fixed deposits having respective annual interest rates in the ratio 6: 5: 4. What is their total interest income (in Rs) after a year, if Bina's interest income exceeds Amala's by Rs 250?

A.7000
B.6000
C.6350
D.7250
Arithmetic/Ratio and Proportion/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
Amala, Bina, and Gouri invest money in the ratio 3: 4: 5 in fixed deposits having respective annual interest rates in the ratio 6: 5: 4. What is their total interest income (in Rs) after a year, if Bina's interest income exceeds Amala's by Rs 250? A) 7000 B) 6000 C) 6350 D) 7250

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QA2019MCQeasy

If m and n are integers such that (οƒ–2)19 34 42 9m 8n = 3n 16m ( 4 64 ) then m is

A.-16
B.-24
C.-12
D.-20
Algebra/Progressions/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
If m and n are integers such that (οƒ–2)19 34 42 9m 8n = 3n 16m ( 4 64 ) then m is A) -16 B) -24 C) -12 D) -20

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QA2019MCQmedium

A chemist mixes two liquids 1 and 2. One litre of liquid 1 weighs 1 kg and one litre of liquid 2 weighs 800 gm. If half litre of the mixture weighs 480 gm, then the percentage of liquid 1 in the mixture, in terms of volume, is

A.70
B.85
C.80
D.75
Arithmetic/Percentages/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
A chemist mixes two liquids 1 and 2. One litre of liquid 1 weighs 1 kg and one litre of liquid 2 weighs 800 gm. If half litre of the mixture weighs 480 gm, then the percentage of liquid 1 in the mixture, in terms of volume, is A) 70 B) 85 C) 80 D) 75

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QA2019MCQeasy

Let x and y be positive real numbers such that log5 (x + y) + log5 (x βˆ’y) = 3, and log2 y βˆ’log2 x = 1 βˆ’log2 3. Then xy equals

A.25
B.150
C.250
D.100
Algebra/Linear Equations/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
Let x and y be positive real numbers such that log5 (x + y) + log5 (x βˆ’y) = 3, and log2 y βˆ’log2 x = 1 βˆ’log2 3. Then xy equals A) 25 B) 150 C) 250 D) 100

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QA2019MCQmedium

If the rectangular faces of a brick have their diagonals in the ratio 3: 2√3: √15, then the ratio of the length of the shortest edge of the brick to that of its longest edge is

A.1: √3
B.2: √5
C.√2: √3
D.3: 2
Arithmetic/Time and Work/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
If the rectangular faces of a brick have their diagonals in the ratio 3: 2√3: √15, then the ratio of the length of the shortest edge of the brick to that of its longest edge is A) 1: βˆšπŸ‘ B) 2: √5 C) √2: √3 D) 3: 2

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QA2019TITAeasy

Let S be the set of all points (x, y) in the x-y plane such that |x| + |y| ≀2 and |x| β‰₯1. Then, the area, in square units, of the region represented by S equals [TITA]

Geometry/Coordinate Geometry/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
Let S be the set of all points (x, y) in the x-y plane such that |x| + |y| ≀2 and |x| β‰₯1. Then, the area, in square units, of the region represented by S equals [TITA] Answer: 2

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QA2019TITAeasy

The number of solutions of the equation |x|(6x2+1) = 5x2 is [TITA]

Arithmetic/Mixtures and Alligation/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
The number of solutions of the equation |x|(6x2+1) = 5x2 is [TITA] Answer: 5

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QA2019TITAmedium

Three men and eight machines can finish a job in half the time taken by three machines and eight men to finish the same job. If two machines can finish the job in 13 days, then how many men can finish the job in 13 days? [TITA]

Arithmetic/Time and Work/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
Three men and eight machines can finish a job in half the time taken by three machines and eight men to finish the same job. If two machines can finish the job in 13 days, then how many men can finish the job in 13 days? [TITA] Answer: 13

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QA2019MCQeasy

The product of the distinct roots of |x2 βˆ’x βˆ’6| = x + 2 is

A.-4
B.βˆ’16
C.-8
D.-24
Algebra/Quadratic Equations/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
The product of the distinct roots of |x2 βˆ’x βˆ’6| = x + 2 is A) -4 B) βˆ’16 C) -8 D) -24

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QA2019MCQmedium

The wheels of bicycles A and B have radii 30 cm and 40 cm, respectively. While traveling a certain distance, each wheel of A required 5000 more revolutions than each wheel of B. If bicycle B traveled this distance in 45 minutes, then its speed, in km per hour, was

A.18Ο€
B.16Ο€
C.12Ο€
D.14Ο€
Arithmetic/Time Speed Distance/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
The wheels of bicycles A and B have radii 30 cm and 40 cm, respectively. While traveling a certain distance, each wheel of A required 5000 more revolutions than each wheel of B. If bicycle B traveled this distance in 45 minutes, then its speed, in km per hour, was A) 18Ο€ B) 16Ο€ C) 12Ο€ D) 14Ο€

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QA2019TITAmedium

Consider a function f (x+y) = f (x) f (y) where x,y are positive integers, and f (1) = 2. If f (a+1) + f (a+2) + ….. + f(a+n) = 16 (2n-1) then a is equal to. [TITA]

Algebra/Functions/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
Consider a function f (x+y) = f (x) f (y) where x,y are positive integers, and f (1) = 2. If f (a+1) + f (a+2) + ….. + f(a+n) = 16 (2n-1) then a is equal to. [TITA] Answer: 3

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QA2019MCQhard

Ramesh and Gautam are among 22 students who write an examination. Ramesh scores 82.5. The average score of the 21 students other than Gautam is 62. The average score of all the 22 students is one more than the average score of the 21 students other than Ramesh. The score of Gautam is

A.51
B.53
C.49
D.48
Arithmetic/Ratio and Proportion/data/extracted_text/2019/Slot_1/QA/CAT_2019_Slot_1_QA.txt
Ramesh and Gautam are among 22 students who write an examination. Ramesh scores 82.5. The average score of the 21 students other than Gautam is 62. The average score of all the 22 students is one more than the average score of the 21 students other than Ramesh. The score of Gautam is A) 51 B) 53 C) 49 D) 48

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QA2019MCQmedium

The real root of the equation 26x + 23x+2 – 21 = 0 is

A.π‘™π‘œπ‘”23 3
B.log29
C.π‘™π‘œπ‘”27 3
D.log227
Algebra/Logarithms/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
The real root of the equation 26x + 23x+2 – 21 = 0 is A) π’π’π’ˆπŸπŸ‘ πŸ‘ B) log29 C) π‘™π‘œπ‘”27 3 D) log227

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QA2019MCQeasy

The average of 30 integers is 5. Among these 30 integers, there are exactly 20 which do not exceed 5. What is the highest possible value of the average of these 20 integers?

A.4
B.5
C.4.5
D.3.5
Arithmetic/Averages/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt

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QA2019MCQeasy

Let a, b, x, y be real numbers such that a2+b2 = 25, x2+y2 = 169 and ax + by = 65. If k = ay - bx, then

A.k = 0
B.k > 5 13
C.k = 5 13
D.0 < k ο‚£ 5 13
Algebra/Quadratic Equations/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
Let a, b, x, y be real numbers such that a2 + b2 = 25, x2 + y2 = 169 and ax + by = 65. If k = ay - bx, then A) k=0 B) k > 5 13 C) k = 5 13 D) 0 < k ο‚£ 5 13

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QA2019MCQmedium

In a triangle ABC, medians AD and BE are perpendicular to each other, and have lengths 12 cm and 9 cm, respectively. Then, the area of triangle ABC, in sq cm, is

A.80
B.68
C.72
D.78
Geometry/Triangles/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
In a triangle ABC, medians AD and BE are perpendicular to each other, and have lengths 12 cm and 9 cm, respectively. Then, the area of triangle ABC, in sq cm, is A) 80 B) 68 C) 72 D) 78

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QA2019MCQeasy

Let a1, a2,…be integers such that a1 – a2 + a3 – a4 + ……. (-1)n-1 an = n, for n ο‚³1. Then a51 + a52 + …. + a1023 equals

A.βˆ’1
B.1
C.0
D.10
Algebra/Progressions/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
Let a1, a2 be integers such that a1 – a2 + a3 – a4 + ……. (-1)n-1 an = n, for n ο‚³1. Then a51 + a52 + …. + a1023 equals A) βˆ’1 B) 1 C) 0 D) 10

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QA2019TITAeasy

How many factors of 24 x 35 x 104 are perfect squares which are greater than 1? [TITA]

Number System/Divisibility/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
How many factors of 24 x 35 x 104 are perfect squares which are greater than 1? [TITA] Answer: 44

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QA2019MCQmedium

Two circles, each of radius 4 cm, touch externally. Each of these two circles is touched externally by a third circle. If these three circles have a common tangent, then the radius of the third circle, in cm, is

A.Ο€/3
B.1
C.1/√2
D.√2
Geometry/Circles/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
Two circles, each of radius 4 cm, touch externally. Each of these two circles is touched externally by a third circle. If these three circles have a common tangent, then the radius of the third circle, in cm, is A) Ο€/3 B) 1 C) 1/√2 D) √2

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QA2019MCQeasy

What is the largest positive integer such that 𝑛2+7𝑛+12 𝑛2βˆ’π‘›βˆ’12 is also positive integer?

A.6
B.8
C.16
D.12
Algebra/Quadratic Equations/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
What is the largest positive integer such that 𝑛2+7𝑛+12 𝑛2βˆ’π‘›βˆ’12 is also positive integer? A) 6 B) 8 C) 16 D) 12

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QA2019MCQmedium

In 2010, a library contained a total of 11500 books in two categories - fiction and non-fiction. In 2015, the library contained a total of 12760 books in these two categories. During this period, there was 10% increase in the fiction category while there was 12% increase in the non-fiction category. How many fiction books were in the library in 2015?

A.6600
B.6160
C.6000
D.5500
Arithmetic/Percentages/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
In 2010, a library contained a total of 11500 books in two categories - fiction and non-fiction. In 2015, the library contained a total of 12760 books in these two categories. During this period, there was 10% increase in the fiction category while there was 12% increase in the non-fiction category. How many fiction books were in the library in 2015? A) 6600 B) 6160 C) 6000 D) 5500

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QA2019TITAmedium

Let f be a function such that f (mn) = f (m) f (n) for every positive integers m and n. If f (1), f (2) and f (3) are positive integers, f (1) < f (2), and f (24) = 54, then f (18) equals [TITA]

Algebra/Functions/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
Let f be a function such that f (mn) = f (m) f (n) for every positive integers m and n. If f (1), f (2) and f (3) are positive integers, f (1) < f (2), and f (24) = 54, then f (18) equals [TITA] Answer: 12

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QA2019TITAmedium

Let A and B be two regular polygons having a and b sides, respectively. If b = 2a and each interior angle of B is 3/2 times each interior angle of A, then each interior angle, in degrees, of a regular polygon with a + b sides is [TITA]

Algebra/Linear Equations/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
Let A and B be two regular polygons having a and b sides, respectively. If b = 2a and each interior angle of B is 3/2 times each interior angle of A, then each interior angle, in degrees, of a regular polygon with a + b sides is [TITA] Answer: 150

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QA2019MCQmedium

A cyclist leaves A at 10 am and reaches B at 11 am. Starting from 10:01 am, every minute a motorcycle leaves A and moves towards B. Forty-five such motorcycles reach B by 11 am. All motorcycles have the same speed. If the cyclist had doubled his speed, how many motorcycles would have reached B by the time the cyclist reached B?

A.22
B.20 15
D.23
Arithmetic/Time Speed Distance/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
A cyclist leaves A at 10 am and reaches B at 11 am. Starting from 10:01 am, every minute a motorcycle leaves A and moves towards B. Forty-five such motorcycles reach B by 11 am. All motorcycles have the same speed. If the cyclist had doubled his speed, how many motorcycles would have reached B by the time the cyclist reached B? A) 22 B) 20 B) 15 D) 23

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QA2019MCQeasy

Let A be a real number. Then the roots of the equation x2 βˆ’4x – log2A = 0 are real and distinct if and only if

A.A < 1/16
B.A > 1/8
C.A > 1/16
D.A < 1/8
Algebra/Quadratic Equations/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
Let A be a real number. Then the roots of the equation x2 βˆ’4x – log2A = 0 are real and distinct if and only if A) A < 1/16 B) A > 1/8 C) A > 1/16 D) A < 1/8

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QA2019TITAmedium

John jogs on track A at 6 kmph and Mary jogs on track B at 7.5 kmph. The total length of tracks A and B is 325 metres. While John makes 9 rounds of track A, Mary makes 5 rounds of track B. In how many seconds will Mary make one round of track A? [TITA]

Arithmetic/Time Speed Distance/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
John jogs on track A at 6 kmph and Mary jogs on track B at 7.5 kmph. The total length of tracks A and B is 325 metres. While John makes 9 rounds of track A, Mary makes 5 rounds of track B. In how many seconds will Mary make one round of track A? [TITA] Answer: 48

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QA2019MCQmedium

Anil alone can do a job in 20 days while Sunil alone can do it in 40 days. Anil starts the job, and after 3 days, Sunil joins him. Again, after a few more days, Bimal joins them and they together finish the job. If Bimal has done 10% of the job, then in how many days was the job done?

A.13
B.12
C.15
D.14
Arithmetic/Time and Work/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
Anil alone can do a job in 20 days while Sunil alone can do it in 40 days. Anil starts the job, and after 3 days, Sunil joins him. Again, after a few more days, Bimal joins them and they together finish the job. If Bimal has done 10% of the job, then in how many days was the job done? A) 13 B) 12 C) 15 D) 14

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QA2019MCQmedium

In an examination, Rama's score was one-twelfth of the sum of the scores of Mohan and Anjali. After a review, the score of each of them increased by 6. The revised scores of Anjali, Mohan, and Rama were in the ratio 11:10:3. Then Anjali's score exceeded Rama's score by

A.26
B.32
C.24
D.35
Arithmetic/Ratio and Proportion/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
In an examination, Rama's score was one-twelfth of the sum of the scores of Mohan and Anjali. After a review, the score of each of them increased by 6. The revised scores of Anjali, Mohan, and Rama were in the ratio 11:10:3. Then Anjali's score exceeded Rama's score by A) 26 B) 32 C) 24 D) 35

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QA2019TITAmedium

In an examination, the score of A was 10% less than that of B, the score of B was 25% more than that of C, and the score of C was 20% less than that of D. If A scored 72, then the score of D was [TITA]

Arithmetic/Percentages/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
In an examination, the score of A was 10% less than that of B, the score of B was 25% more than that of C, and the score of C was 20% less than that of D. If A scored 72, then the score of D was [TITA] Answer: 80

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QA2019MCQmedium

The base of a regular pyramid is a square and each of the other four sides is an equilateral triangle, length of each side being 20 cm. The vertical height of the pyramid, in cm, is

A.10√2
B.8√3
C.12
D.5√5
Geometry/Triangles/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
The base of a regular pyramid is a square and each of the other four sides is an equilateral triangle, length of each side being 20 cm. The vertical height of the pyramid, in cm, is A) 10√2 B) 8√3 C) 12 D) 5√5

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QA2019MCQeasy

If x is a real number, then π‘™π‘œπ‘”π‘’ 4π‘₯βˆ’π‘₯2 3 is a real number number if and only if

A.-3 ο‚£x ο‚£3
B.1 ο‚£x ο‚£2
C.1 ο‚£x ο‚£3
D.-1 ο‚£x ο‚£3
Algebra/Logarithms/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
If x is a real number,then π‘™π‘œπ‘”π‘’ 4π‘₯βˆ’π‘₯2 3 is a real number if and only if A) -3 ο‚£x ο‚£3 B) 1 ο‚£x ο‚£2 C) 1 ο‚£x ο‚£3 D) -1 ο‚£x ο‚£3

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QA2019MCQmedium

Let ABC be a right-angled triangle with hypotenuse BC of length 20 cm. If AP is perpendicular on BC, then the maximum possible length of AP, in cm, is

A.10
B.8√2
C.6√2
D.5
Geometry/Triangles/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
Let ABC be a right-angled triangle with hypotenuse BC of length 20 cm. If AP is perpendicular on BC, then the maximum possible length of AP, in cm, is A) 10 B) 8√2 C) 6√2 D) 5

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QA2019MCQmedium

Two ants A and B start from a point P on a circle at the same time, with A moving clock-wise and B moving anti-clockwise. They meet for the first time at 10:00 am when A has covered 60% of the track. If A returns to P at 10:12 am, then B returns to P at

A.10:27 am
B.10:25 am
C.10:45 am
D.10:18 am
Arithmetic/Time Speed Distance/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
Two ants A and B start from a point P on a circle at the same time, with A moving clock-wise and B moving anti-clockwise. They meet for the first time at 10:00 am when A has covered 60% of the track. If A returns to P at 10:12 am, then B returns to P at A) 10:27 am B) 10:25 am C) 10:45 am D) 10:18 am

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QA2019TITAeasy

How many pairs of (m,n) satisfy the equation m2 + 105 = n2? [TITA]

Algebra/Progressions/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
How many pairs of (m,n) satisfy the equation m2 + 105 = n2? [TITA] Answer: 4

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QA2019MCQmedium

The salaries of Ramesh, Ganesh and Rajesh were in the ratio 6:5:7 in 2010, and in the ratio 3:4:3 in 2015. If Ramesh’s salary increased by 25% during 2010-2015, then the percentage increase in Rajesh’s salary during this period is closest to

A.7
B.9
C.8
D.10
Arithmetic/Percentages/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
The salaries of Ramesh, Ganesh and Rajesh were in the ratio 6:5:7 in 2010, and in the ratio 3:4:3 in 2015. If Ramesh’s salary increased by 25% during 2010-2015, then the percentage increase in Rajesh’s salary during this period is closest to A) 7 B) 9 C) 8 D) 10

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QA2019MCQmedium

A man makes complete use of 405 cc of iron, 783 cc of aluminum, and 351 cc of copper to make a number of solid right circular cylinders of each type of metal. These cylinders have the same volume and each of these has radius 3 cm. If the total number of cylinders is to be kept at a minimum, then the total surface area of all these cylinders, in sq cm, is

A.1044(4 + Ο€)
B.8464Ο€
C.928Ο€
D.1026(1 + Ο€)
Geometry/Mensuration/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
A man makes complete use of 405 cc of iron, 783 cc of aluminium, and 351 cc of copper to make a number of solid right circular cylinders of each type of metal. These cylinders have the same volume and each of these has radius 3 cm. If the total number of cylinders is to be kept at a minimum, then the total surface area of all these cylinders, in sq cm, is A) 1044(4 + Ο€) B) 8464Ο€ C) 928Ο€ D) 1026(1 + Ο€)

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QA2019MCQmedium

The quadratic equation x2 + bx + c = 0 has two roots 4a and 3a, where a is an integer. Which of the following is a possible value of b2 + c?

A.3721
B.549
C.361
D.427
Algebra/Quadratic Equations/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
The quadratic equation x2 + bx + c = 0 has two roots 4a and 3a, where a is an integer. Which of the following is a possible value of b2 + c? A) 3721 B) 549 C) 361 D) 427

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QA2019TITAmedium

In a six-digit number, the sixth, that is, the rightmost, digit is the sum of the first three digits, the fifth digit is the sum of first two digits, the third digit is equal to the first digit, the second digit is twice the first digit and the fourth digit is the sum of fifth and sixth digits. Then, the largest possible value of the fourth digit is [TITA]

Algebra/Progressions/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
In a six-digit number, the sixth, that is, the rightmost, digit is the sum of the first three digits, the fifth digit is the sum of first two digits, the third digit is equal to the first digit, the second digit is twice the first digit and the fourth digit is the sum of fifth and sixth digits. Then, the largest possible value of the fourth digit is [TITA] Answer: 7

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QA2019MCQmedium

Mukesh purchased 10 bicycles in 2017, all at the same price. He sold six of these at a profit of 25% and the remaining four at a loss of 25%. If he made a total profit of Rs. 2000, then his purchase price of a bicycle, in Rupees, was

A.2000
B.6000
C.8000
D.4000
Arithmetic/Profit and Loss/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
Mukesh purchased 10 bicycles in 2017, all at the same price. He sold six of these at a profit of 25% and the remaining four at a loss of 25%. If he made a total profit of Rs. 2000, then his purchase price of a bicycle, in Rupees, was A) 2000 B) 6000 C) 8000 D) 4000

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QA2019MCQeasy

The number of common terms in the two sequences: 15, 19, 23, 27,...., 415 and 14, 19, 24, 29,..., 464 is

A.20
B.18
C.21
D.19
Algebra/Progressions/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
The number of common terms in the two sequences: 15, 19, 23, 27,...., 415 and 14, 19, 24, 29,..., 464 is A) 20 B) 18 C) 21 D) 19

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QA2019TITAeasy

If (2n+1) + (2n+3) + (2n+5) + … + (2n+47) = 5280, then what is the value of 1+2+3+...+n? [TITA]

Algebra/Progressions/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
If (2n+1) + (2n+3) + (2n+5) + … + (2n+47) = 5280, then what is the value of 1+2+3+...+n? [TITA] Answer: 4851

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QA2019MCQhard

The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. Each of three vessels A, B, C contains 500 ml of salt solution of strengths 10%, 22%, and 32%, respectively. Now, 100 ml of the solution in vessel A is transferred to vessel B. Then, 100 ml of the solution in vessel B is transferred to vessel C. Finally, 100 ml of the solution in vessel C is transferred to vessel A. The strength, in percentage, of the resulting solution in vessel A is

A.15
B.12
C.13
D.14
Arithmetic/Percentages/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. Each of three vessels A, B, C contains 500 ml of salt solution of strengths 10%, 22%, and 32%, respectively. Now, 100 ml of the solution in vessel A is transferred to vessel B. Then, 100 ml of the solution in vessel B is transferred to vessel C. Finally, 100 ml of the solution in vessel C is transferred to vessel A. The strength, in percentage, of the resulting solution in vessel A is A) 15 B) 12 C) 13 D) 14

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QA2019TITAeasy

If 5x – 3y = 13438 and 5x-1+3y+1 = 9686, then x+y equals [TITA]

Algebra/Linear Equations/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
If 5x – 3y = 13438 and 5x-1+3y+1 = 9686, then x+y equals [TITA] Answer: 13

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QA2019TITAmedium

Amal invests Rs 12000 at 8% interest, compounded annually, and Rs10000 at 6% interest, compounded semi-annually, both investments being for one year. Bimal invests his money at 7.5% simple interest for one year. If Amal and Bimal get the same amount of interest, then the amount, in Rupees, invested by Bimal is [TITA]

Arithmetic/Simple Interest Compound Interest/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
Amal invests Rs 12000 at 8% interest, compounded annually, and Rs.10000 at 6% interest, compounded semi-annually, both investments being for one year. Bimal invests his money at 7.5% simple interest for one year. If Amal and Bimal get the same amount of interest, then the amount, in Rupees, invested by Bimal is [TITA] Answer: 20920

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QA2019MCQmedium

A shopkeeper sells two tables, each procured at cost price p, to Amal and Asim at a profit of 20% and at a loss of 20%, respectively. Amal sells his table to Bimal at a profit of 30%, while Asim sells his table to Barun at a loss of 30%. If the amounts paid by Bimal and Barun are x and y, respectively, then (x βˆ’y) / p equals

A.1
B.1.2
C.0.7
D.0.50
Arithmetic/Profit and Loss/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
A shopkeeper sells two tables, each procured at cost price p, to Amal and Asim at a profit of 20% and at a loss of 20%, respectively. Amal sells his table to Bimal at a profit of 30%, while Asim sells his table to Barun at a loss of 30%. If the amounts paid by Bimal and Barun are x and y, respectively, then (x βˆ’y) / p equals A) 1 B) 1.2 C) 0.7 D) 0.50

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QA2019TITAhard

John gets Rs 57 per hour of regular work and Rs 114 per hour of overtime work. He works altogether 172 hours and his income from overtime hours is 15% of his income from regular hours. Then, for how many hours did he work overtime? [TITA]

Arithmetic/Ratio and Proportion/data/extracted_text/2019/Slot_2/QA/CAT_2019_Slot_2_QA.txt
John gets Rs 57 per hour of regular work and Rs 114 per hour of overtime work. He works altogether 172 hours and his income from overtime hours is 15% of his income from regular hours. Then, for how many hours did he work overtime? [TITA] Answer: 12

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QA2025TITAmedium

In a class, there were more than 10 boys and a certain number of girls. After 40% of the girls and 60% of the boys left the class, the remaining number of girls was 8 more than the remaining number of boys. Then, the minimum possible number of students initially in the class was

Arithmetic/Profit and Loss/data/extracted_text/2025/Slot_1/FULL/CAT_2025_Slot_1_FULL.txt
55 Let the initial number of boys and girls be b and g, respectively. Then, g – 0.4g = b – 0.6b + 8, where b > 10 οƒž 0.6g = 0.4b + 8 οƒžο€ 3g = 2b + 40 οƒž g = (2b + 40)/3 Since b > 10, For b = 11, g = (22 + 40)/3 = 62/3 is not an integer. For b = 12, g = (24 + 40)/3 = 64/3 is not an integer. For b = 13, g = (26 + 40)/3 = 66/3 = 22 is an integer. But 40% of 13 = 5.2 (not an integer) Since 40% of b must be an integer οƒž b must be a multiple of 5. For b = 15, g = (2 Γ— 15 + 40)/3 = 70/3 is not an integer. For b = 20, g = (2 Γ— 20 + 40)/3 = 80/3 is not an integer. For b = 25, g = (2 Γ— 25 + 40)/3 = 90/3 = 30 is an integer. Hence, the minimum number of students in the class was = 25 + 30 = 55.

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QA2025MCQmedium

The number of distinct integers n for which   2 1 4 log n 7n 11 0  οƒΆ  οƒ·  οƒΈ ο€­  ο€Ύ, is

A.0
B.infinite
C.1
D.2
Algebra/Inequalities/data/extracted_text/2025/Slot_1/FULL/CAT_2025_Slot_1_FULL.txt
1 We have   2 1 4 log n 7n 11 0  οƒΆ  οƒ·  οƒΈ ο€­  ο€Ύ Since 0 < 1/4 < 0, so   2 1 4 log n 7n 11 0  οƒΆ  οƒ·  οƒΈ ο€­  ο€Ύ  2 0 n 7n 11 1 ο€Ό ο€­  ο€Ό For n2 – 7n + 11 > 0 7 5 n 2 ο‚± οƒž ο€½ or n = 2.382, 4.618 … (i) For n2 – 7n + 11 < 1 Or (n – 5)(n – 2) < 0 Or 2 < n < 5 … (ii) Combining (i) and (ii), n = 3, 4 For n = 3 or n = 4, n2 – 7n + 11 = – 1 So the inequality   2 1 4 log n 7n 11 0  οƒΆ  οƒ·  οƒΈ ο€­  ο€Ύ is not satisfy at n = 3 or n = 4. Hence, the answer is 0.

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QA2025MCQmedium

Shruti travels a distance of 224 km in four parts for a total travel time of 3 hours. Her speeds in these four parts follow an arithmetic progression, and the corresponding time taken to cover these four parts follow another arithmetic progression. If she travels at a speed of 960 meters per minute for 30 minutes to cover the first part, then the distance, in meters, she travels in the fourth part is

A.112000
B.76800
C.96000
D.86400
Arithmetic/Time Speed Distance/data/extracted_text/2025/Slot_1/FULL/CAT_2025_Slot_1_FULL.txt
4 Total distance travelled = 224 km = 224000 m Total time taken = 3 hours = 180 minutes Since the times taken are in arithmetic progression, they are: 30, 30 + t, 30 + 2t, 30 + 3t 26 CAT 2025 Solved Paper (Slot-1) So 30 + (30 + t) + (30 + 2t) + (30 + 3t) = 180 οƒž 30 Γ— 4 + 6t = 180 οƒž t = 10 So the times are 30, 40, 50, 60 minutes. Since the speeds are also in arithmetic progression, they are: 960, (960 + d), (960 + 2d), (960 + 3d) m/minute So 960 Γ— 30 + (960 + d) Γ— 40 + (960 + 2d) Γ— 50 + (960 + 3d) Γ— 60 = 224000 οƒž 172800 + 320d = 224000 οƒž 172800 + 320d = 224000 οƒž d = 160 Hence, the distance travelled in the fourth part = (960 + 3 Γ— 160) Γ— 60 = 86400 m.

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QA2025MCQmedium

The (x, y) coordinates of vertices P, Q and R of a parallelogram PQRS are (–3, –2), (1, –5) and (9, 1), respectively. If the diagonal SQ intersects the x-axis at (a, 0), then the value of a is

A.29/9
B.13/4
C.27/7
D.10/3
Geometry/Coordinate Geometry/data/extracted_text/2025/Slot_1/FULL/CAT_2025_Slot_1_FULL.txt
1 (–3, –2) P Q (1, –5) (p, q) S R (9, 1) O Co-ordinates of O are: (– 3 + 9)/2, (– 2 + 1)/2 = (3, – 1/2) So (p + 1)/2 = 3 οƒž p = 5 and (q – 5)/2 = – 1/2 οƒž q = 4 The co-ordinates of vertex S is (5, 4). Slope of SQ = (– 5 – 4)/(1 – 5) = 9/4 The equation of line SQ is (y – 4) = 9/4 (x – 5) = 0 οƒž 9x – 4y = 29 This line intersects x-axis at (a, 0). So 9a – 0 = 29 οƒž a = 29/9.

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QA2025MCQmedium

In a circle with center C and radius 6 2 cm, PQ and SR are two parallel chords separated by one of the diameters. If PQC = 45Β°, and the ratio of the perpendicular distance of PQ and SR from C is 3: 2, then the area, in sq. cm, of the quadrilateral PQRS is

A.  4 3 2 7 
B.  20 3 14 
C.  4 3 14 
D.  20 3 2 7 
Geometry/Circles/data/extracted_text/2025/Slot_1/FULL/CAT_2025_Slot_1_FULL.txt
2 45Β° 6 2 cm οƒ– 6 2 cm οƒ– M N Q R C P S 3k 2k Since MQC = 45Β° Then, MQ = CM = 3k In right angled triangle CMQ, (3k)2 + (3k)2 = (6οƒ–2)2 οƒž 18k2 = 72 οƒž k = 2 So CM = MQ = 6 cm, PQ = 12 cm NR = οƒ–((6οƒ–2)2 – 42) = οƒ–(72 – 16) = 2οƒ–14 cm So SR = 4οƒ–14 cm Hence, the area of quadrilateral PQRS = 1/2 Γ— (12 + 4οƒ–14) Γ— 10 = 20(3 + οƒ–14) sq. cm.

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QA2025TITAmedium

Stocks A, B and C are priced at rupees 120, 90 and 150 per share, respectively. A trader holds a portfolio consisting of 10 shares of stock A, and 20 shares of stocks B and C put together. If the total value of her portfolio is rupees 3300, then the number of shares of stock B that she holds, is

Arithmetic/Profit and Loss/data/extracted_text/2025/Slot_1/FULL/CAT_2025_Slot_1_FULL.txt
15 Let n be the number of stocks B. Then, the number of stocks C = 20 – n So 10 Γ— 120 + 90n + (20 – n) Γ— 150 = 3300 οƒž 1200 + 90n + 3000 – 150n = 3300 οƒž 60n = 900 οƒž n = 15.

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QA2025MCQeasy

In the set of consecutive odd numbers {1, 3, 5,..., 57}, there is a number k such that the sum of all the elements less than k is equal to the sum of all the elements greater than k. Then, k equals

A.43
B.39
C.37
D.41
Algebra/Quadratic Equations/data/extracted_text/2025/Slot_1/FULL/CAT_2025_Slot_1_FULL.txt
4 1 + 3 + 5 + … n terms = n2 So 1 + 3 + 5 + … + 57 = 292 = 841 1 + 3 + 5 + … + (k – 2), k, (k + 2) + k + 4, … + 57 Let 1 + 3 + 5 + … + (k – 2) = (k + 2) + k + 4, … + 57 = x2 Then, x2 + k + x2 = 841 οƒž x2 = (841 – k)/2 Option (1): k = 43, x2 = (841 – 43)/2 = 399 οƒž x = οƒ–399 Option (2): k = 39, x2 = (841 – 39)/2 = 401 οƒž x = οƒ–401 Option (3): k = 37, x2 = (841 – 37)/2 = 402 οƒž x = οƒ–402 Option (2): k = 41, x2 = (841 – 41)/2 = 400 οƒž x = 20 Hence, option (4) is the correct answer.

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QA2025TITAmedium

Kamala divided her investment of Rs. 10,0000 between stocks, bonds, and gold. Her investment in bonds was 25% of her investment in gold. With annual returns of 10%, 6%, 8% on stocks, bonds, and gold, respectively, she gained a total amount of Rs. 8,200 in one year. The amount, in rupees, that she gained from the bonds, was

Arithmetic/Ratio and Proportion/data/extracted_text/2025/Slot_1/FULL/CAT_2025_Slot_1_FULL.txt
900 Let Kamala invested her money in stocks and gold be Rs.x and Rs.y, respectively. Then, x + 0.25y + y = 100000 CAT 2025 Solved Paper (Slot-1) 27 οƒž x + 1.25y = 100000 … (i) And 0.1x + 0.06 Γ— 0.25y + 0.08y = 8200 οƒž x + 0.95y = 82000 … (ii) From (i) and (ii), 0.3y = 18000 οƒž y = Rs.60,000 So amount invested in bonds = 0.25 Γ— 60000 = Rs.15,000 Hence, the amount gained by Kamala from the bonds = 15000 Γ— 0.06 = Rs.900.

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QA2025MCQmedium

A cafeteria offers 5 types of sandwiches. Moreover, for each type of sandwich, a customer can choose one of 4 breads and opt for either small or large sized sandwich. Optionally, the customer may also add up to 2 out of 6 available sauces. The number of different ways in which an order can be placed for a sandwich, is

A.880
B.840
C.800
D.600
Modern Math/Permutation Combination/data/extracted_text/2025/Slot_1/FULL/CAT_2025_Slot_1_FULL.txt
1 There are 5 types of sandwiches. For each sandwich, the customer can choose 1 of 4 breads. Each sandwich can be either small or large = 2 choices. The customer may add up to 2 sauces from 6 available sauces. Hence, the total number of ways = 5 Γ— 4 Γ— 2 Γ— (6C0 + 6C1 + 6C2) = 40 Γ— (1 + 6 + 15) = 880

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QA2025MCQmedium

A value of c for which the minimum value of f(x) = x2 – 4cx + 8c is greater than the maximum value of g(x) = –x2 + 3cx – 2c, is

A.–2
B.–1/2
C.2
D.1/2
Algebra/Quadratic Equations/data/extracted_text/2025/Slot_1/FULL/CAT_2025_Slot_1_FULL.txt
4 The function f(x) = x2 – 4cx + 8c has a minimum at xmin = 4c/2 = 2c So the minimum value = f(2c) = (2c)2 – 4c Γ— 2c + 8c =– 4c2 + 8c The function g(x) = – x2 + 3cx – 2c has a maximum at xmax = –3c/2(–1) = 3c/2 So the maximum value = f(3c/2) = – (3c/2)2 + 3c Γ— 3c/2 – 2c = 9c2/4 – 2c According to the question, – 4c2 + 8c > 9c2/4 – 2c Or, – 25c2 – 40c > 0 Or, 5c(5c – 8) < 0 If c < 0 and 5c – 8 > 0 οƒž c > 8/5, not possible. If c > 0 and 5c – 8 < 0 οƒž c < 8/5, which is possible. So 0 < c < 8/5 Hence, c = 1/2 is the correct option.

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QA2025MCQhard

Let 3 x 6 ο‚£ ο‚£ and [x2] = [x]2, where [x] is the greatest integer not exceeding x. If set S represents all feasible values of x, then a possible subset of S is

A.   3, 10 5, 26 {6}  οƒˆ οƒˆ 
B.  4, 18 [5, 27) {6} οƒˆ οƒˆ
C.3, 10 5, 26  οƒΉ  οƒΉ οƒˆ    
D.3, 10 4, 17 {6}  οƒΉ  οƒΉ οƒˆ οƒˆ    
Algebra/Quadratic Equations/data/extracted_text/2025/Slot_1/FULL/CAT_2025_Slot_1_FULL.txt
1 Since 3 ο‚£ x ο‚£ 6, possible values of [x] are: 3, 4, 5, 6 Case 1: 3 ο‚£ x < 4 οƒž [x] = 3 Then, [x]2 = 9 [x2] = 9 οƒž 9 ο‚£ x2 < 10 Or, 3 < x < οƒ–10 So x [ (3, οƒ–10) Case 2: 4 ο‚£ x < 5 οƒž [x] = 4 Then, [x]2 = 16 [x2] = 16 οƒž 16 ο‚£ x2 < 17 Or, 4 ο‚£ x < οƒ–17 But οƒ–17 = 4.12, so this interval is very small and does not satisfy the equality consistently over the whole range. Hence, no valid interval is included here. Case 3: 5 ο‚£ x < 6 οƒž [x] = 5 Then, [x]2 = 25 [x2] = 25 οƒž 25 ο‚£ x2 < 26 Or, 5 ο‚£ x < οƒ–26 So x [ [5, οƒ–26) Case 4: x = 6 οƒž [x] = 6 Then, [x]2 = 36, [x2] = 36 So x = 6 Hence, a possible subset of S is (3, οƒ–10) οƒˆ [5, οƒ–26) οƒˆ {6}.

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QA2025TITAhard

The number of distinct pairs of integers (x, y) satisfying the inequalities x > y ο‚³ 3 and x + y < 14 is 13

Algebra/Linear Equations/data/extracted_text/2025/Slot_1/FULL/CAT_2025_Slot_1_FULL.txt
16 x > y ο‚³ 3 οƒž x ο‚³ y + 1 x + y < 14 οƒž x < 14 – y So y + 1 ο‚£ x < 14 – y οƒž y + 1 < 14 – y οƒž y < 6.5 and y ο‚³ 3 So possible integer values of y are: 3, 4, 5, 6 If y = 3; 4 ο‚£ x < 11 οƒž x = 4, 5, 6, 7, 8, 9, 10 If y = 4; 5 ο‚£ x < 10 οƒž x = 5, 6, 7, 8, 9 If y = 5; 6 ο‚£ x < 9 οƒž x = 6, 7, 8 If y = 6; 7 ο‚£ x < 8 οƒž x = 7 Hence, there are 16 distinct pairs of integers.

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QA2025MCQmedium

At a certain simple rate of interest, a given sum amounts to Rs. 13,920 in 3 years, and to Rs. 18,960 in 6 years and 6 months. If the same given sum had been invested for 2 years at the same rate as before but with interest compounded every 6 months, then the total interest earned, in rupees, would have been nearest to

A.3096
B.3221
C.3150
D.3180
Arithmetic/Simple Interest Compound Interest/data/extracted_text/2025/Slot_1/FULL/CAT_2025_Slot_1_FULL.txt
2 Let the given sum be Rs. P and the simple interest rate be r% per annum. Then, P(1 + 3r/100) = 13920 … (i) And P(1 + 6.5r/100) = 18960 … (ii) From (i) and (ii), (1 + 6.5r/100)/(1 + 3r/100) = 18960/13920 = 79/58 οƒž 58 + 3.77r = 79 + 2.37r οƒž 1.4r = 21 οƒž r = 15% So from (i), P = 13920/1.45 = Rs.9,600 Hence, the required interest earned = 9600(1 + 7.5/100)4 – 9600 ο‚» 12820.50 – 9600 ο‚» Rs.3,221.

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QA2025MCQmedium

A container holds 200 litres of a solution of acid and water, having 30% acid by volume. Atul replaces 20% of this solution with water, then replaces 10% of the resulting solution with acid, and finally replaces 15% of the solution thus obtained, with water. The percentage of acid by volume in the final solution obtained after these three replacements, is nearest to

A.27
B.25
C.23
D.29
Arithmetic/Mixtures and Alligation/data/extracted_text/2025/Slot_1/FULL/CAT_2025_Slot_1_FULL.txt
1 In 200 liter solution, acid = 0.3 Γ— 200 = 60 liter and water = 140 liter 20% of 200 = 40 liter In 40 liter solution, acid = 0.3 Γ— 40 = 12 liter and water = 28 liter 28 CAT 2025 Solved Paper (Slot-1) Now, in 200 liter solution, acid = 60 – 12 = 48 liter and water = 140 – 28 + 40 = 152 liter Acid % = 48/200 Γ— 100 = 24%, water % = 76% 10% of 200 = 20 liters In 20 liters, acid = 0.24 Γ— 20 = 4.8 liter and water = 15.2 liter Now, in 200 liter solution, acid = 48 – 4.8 + 20 = 63.2 liter and water = 152 – 15.2 = 136.8 liter Acid % = 63.2/200 Γ— 100 = 31.6%, water % = 68.4% 15% of 200 = 30 liters In 30 liters, acid = 0.316 Γ— 30 = 9.48 liters and water = 30 – 9.48 = 20.52 liter Now, in 200 liter solution, acid = 63.2 – 9.48 = 53.72 liter and water = 136.8 – 20.52 + 30 = 146.28 liter Now, acid % = 53.72/200 Γ— 100 = 26.86% ο‚» 27%.

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QA2025TITAhard

The number of non-negative integer values of k for which the quadratic equation x2 – 5x + k = 0 has only integer roots, is

Algebra/Quadratic Equations/data/extracted_text/2025/Slot_1/FULL/CAT_2025_Slot_1_FULL.txt
3 The equation x2 – 5x + k = 0 has integer roots. Then, (– 5)2 – 4k = 25 – 4k = Perfect square ο‚³ 0 k 0 1 2 3 4 5 6 25 - 4k 25 21 17 13 9 5 1 Hence, k = 0, 4, 6

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A shopkeeper offers a discount of 22% on the marked price of each chair, and gives 13 chairs to a customer for the discounted price of 12 chairs to earn a profit of 26% on the transaction. If the cost price of each chair is Rs. 100, then the marked price, in rupees, of each chair is

Arithmetic/Profit and Loss/data/extracted_text/2025/Slot_1/FULL/CAT_2025_Slot_1_FULL.txt
175 The cost price of each chair is Rs.100. Let the marked price of each chair be x. Then, selling price of each chair = 0.78x Total cost price of 13 chairs = Rs.1,300 Selling price of 12 chairs = 1300 Γ— 1.26 = Rs.1,638 Selling price of each chair = 1,638/12 = Rs.136.50 Hence, the marked price of each chair = 136.50/0.78 = Rs.175.

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In a 3-digit number N, the digits are non-zero and distinct such that none of the digits is a perfect square, and only one of the digits is a prime number. Then, the number of factors of the minimum possible value of N is

Number System/Divisibility/data/extracted_text/2025/Slot_1/FULL/CAT_2025_Slot_1_FULL.txt
6 1, 4, 9 are perfect square digits. The remaining digits are 2, 3, 5, 6, 7, 8. Out of these 2, 3, 5, 7 are prime numbers and 6, 8 are non-prime numbers. Since only one digit must be prime, the other two must be non-prime. So minimum possible value of N = 268 = 22 Γ— 67 Hence, the number of factors is (2 + 1) Γ— (1 + 1) = 6.

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QA2025TITAeasy

If the length of a side of a rhombus is 36 cm and the area of the rhombus is 396 sq. cm, then the absolute value of the difference between the lengths, in cm, of the diagonals of the rhombus is

Geometry/Quadrilaterals/data/extracted_text/2025/Slot_1/FULL/CAT_2025_Slot_1_FULL.txt
60 d1 2 d2 2 36 cm 36 cm 36 cm 36 cm Area of rhombus = 396 οƒž 1/2 Γ— d1 Γ— d2 = 396 οƒž d1d2 = 792 … (i) (d1/2)2 + (d2/2)2 = 362 οƒž (d1/2)2 + (d2/2)2 = 362 οƒž (d1)2 + (d2)2 = 5184 … (ii) So (d1 – d2)2 = (d1)2 + (d2)2 – 2d1d2 οƒžο€ (d1 – d2)2 = 5184 – 2 Γ— 792 = 3600 οƒžο€ |d1 – d2| = 60 cm.

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The ratio of the number of students in the morning shift and afternoon shift of a school was 13: 9. After 21 students moved from the morning shift to the afternoon shift, this ratio became 19: 14. Next, some new students joined the morning and afternoon shifts in the ratio 3: 8 and then the ratio of the number of students in the morning shift and the afternoon shift became 5: 4. The number of new students who joined is

A.99
B.88
C.121
D.110
Arithmetic/Profit and Loss/data/extracted_text/2025/Slot_1/FULL/CAT_2025_Slot_1_FULL.txt
1 Let the number of students in the morning and afternoon shift be 13x and 9x, respectively. Then, (13x – 21)/(9x + 21) = 19 /14 οƒž 182x – 294 = 171x + 399 οƒž 11x = 693 οƒž x = 63 So number of student in the morning shift = 819 and in the afternoon shift = 567 Let the number of new students joined the morning and afternoon shifts be 3y and 8y, respectively. Then, (819 – 21 + 3y)/(567 + 21 + 8y) = 5/4 οƒž 3192 + 12y = 2940 + 40y οƒž 28y = 252 οƒž y = 9 Hence, the new student joined = 9 Γ— (3 + 8) = 99.

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Arun, Varun and Tarun, if working alone, can complete a task in 24, 21, and 15 days, respectively. They charge Rs. 2,160, Rs. 2,400, and Rs. 2,160 per day, respectively, even if they are employed for a partial day. On any given day, any of the workers may or may not be employed to work. If the task needs to be completed in 10 days or less, then the minimum possible amount, in rupees, required to be paid for the entire task is 14

A.47040
B.34400
C.38880
D.38400
Arithmetic/Time and Work/data/extracted_text/2025/Slot_1/FULL/CAT_2025_Slot_1_FULL.txt
4 Total work = LCM (24, 21, 15) = 840 units Work done per day by Arun, Varun, and Tarun = 840/24, 840/21, 840/15 = 35, 40, 56 units Rs./unit charge by Arun, Varun, and Tarun = 432/ 7, 60, 270/7 So Tarun completes in 10 days = 10 Γ— 56 = 560 units The remaining work 840 – 560 = 280 units completes by Varun in 7 days Hence, the minimum possible amount required to be paid for the entire task is = 2160 Γ— 10 + 2400 Γ— 7 = 21600 + 16800 = Rs.38,400.

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In a ABC, points D and E are on the sides BC and AC, respectively. BE and AD intersect at point T such that AD: AT = 4: 3, and BE: BT = 5: 4. Point F lies on AC such that DF is parallel to BE. Then, BD: CD is

A.7: 4
B.15: 4
C.9: 4
D.11: 4
Arithmetic/Profit and Loss/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
4 A B C D 4y 3x y E F x T In ADF, AT 3 ET AD 4 DF ο€½ ο€½ 4y DF 3 οƒž ο€½ ο€½ ο€½ ο€½ BC BE 5y 15 4y DC DF 4 3 BD BC DC BC 15 11 1 1 DC DC DC 4 4 ο€­ ο€½ ο€½ ο€­ ο€½ ο€­ ο€½

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Let f(x) = x x and g(x). (2x 1) (x 1) ο€½ ο€­ ο€­ Then, the domain of the function h(x) = f(g(x)) + g(f(x)) is all real numbers except

A.1/2, 1, and 3/2
B.–1/2, 1/2, and 1
C.–1, 1/2, and 1
D.1/2, and 1
Algebra/Functions/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
3 h(x) = f(g(x)) + g(f(x))     8 x f x 2g x 1 f x 1 ο€½  ο€­ ο€­ x x 4 1 2x 1 2x x 1 x 1 2x 1 ο€­ ο€­ ο€½  ο€­ ο€­ ο€­ x x x 1 1 x ο€½   ο€­ h(x) ο€½ ο€­ 2 2x (1 x ) for h(x) to be difined x cannot take values + 1 or –1 for f(x) to be defined 1 x 2  Ans: –1, 1/2, 1

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The set of all real values of x for which (x2 – |x + 9| + x) > 0, is

A.(–9, –3) οƒˆ (3, ο‚₯)
B.(–ο‚₯, –9) οƒˆ (3, ο‚₯)
C.(–ο‚₯, –3) οƒˆ (3, ο‚₯)
D.(–ο‚₯, –9) οƒˆ (9, ο‚₯)
Algebra/Quadratic Equations/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
3 x2 – |x + 9| + x > 0 For x = 4 the expression becomes: (4)2 – |4 + 9| + 4 = 16 – 13 + 4 = 8 > 0 So option 4 is discarded For x = –10; (–10)2 – | –10 + 9| + (–10) 100 – 1 > 0  option 1 is discarded. Now x = –4; (–4)2 – |– 4 + 9| + (–5) 16 – 5 – 5 > 0  option 2 is discarded. Here answer is    , 3 3, ο€­ο‚₯ο€­ οƒˆ ο‚₯ Hence, correct answer is option 3.

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If 2 2 x 2x 3 x 2x 2 9 4(3 ) 27 0,  ο€­  ο€­ ο€­  ο€½ then the product of all possible values of x is

A.5
B.30
C.20
D.15
Algebra/Quadratic Equations/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
3 2 2 x 2x 2 x 2x 3 9 4.3 27 0  ο€­  ο€­ο€­  ο€½     2 2 x 2x 3 1 x 2x 3 2 3 4.3 27 0    ο€­ ο€­  ο€½ 2 2 2 x 2x 3 x 2x 3 3 4.3 3 27 0  ο€­  ο€­  οƒΆ  οƒΆ ο€­  ο€½  οƒ·  οƒ·  οƒΈ  οƒΈ Let 2 x 2x 3 3 t  ο€­ ο€½ t2 – 12t + 27 = 0 t = 9, 3 2 x 2x 3 3 9  ο€­  ο€½ or 2 x 2x 3 3 3  ο€­ ο€½ 2 x 2x 3 2 3 3  ο€­  ο€½ or 2 x 2x 3 1 3 3  ο€­ ο€½ x2 + 2x – 3 = 2 or x2 + 2x – 3 = 1 x2 + 2x – 5 = 0 or x2 + 2x – 4 = 0. 5  or 4   Product of all possible value = (–5) (–4) So we have the final table as follows: PI 10 20 30 40 50 60 70 80 90 City / NUR NUR NUR Blusterburg NUR Noodleton Splutterville Quackford Mumpypore Zingaloo Weighted PI 5 10 7.5 20 12.5 15 17.5 20 22.5 State Fogglia Whimshire Humbleset Humbleset Fogglia Whimshire Fogglia Whimshire Humbleset 26 CAT 2025 Solved Paper (Slot-2)

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Ankita is twice as efficient as Bipin, while Bipin is twice as efficient as Chandan. All three of them start together on a job, and Bipin leaves the job after 20 days. If the job got completed in 60 days, the number of days needed by Chandan to complete the job alone, is

Arithmetic/Time and Work/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
340 Let Chandan’s efficiency = 1 unit/day. Then Bipin’s efficiency = 2 units/day (twice Chandan) Ankita’s efficiency = 4 units/day (twice Bipin) So, combined efficiency of all three = 1 + 2 + 4 = 7 units/day Work done in the first 20 days when all three are working = 20 Γ— 7 = 140 units After Bipin leaves, remaining workers are Ankita (4 units/day) and Chandan (1 unit/day) Work done in next 40 days = 40 Γ— 5 = 200 units Total work = 140 + 200 = 340 units Chandan’s efficiency is 1 unit per day. Time taken by Chandan alone = 340/1 = 340 days.

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If log64 x2 + log8 οƒ–y + 3 log512(οƒ–y z) = 4, where x, y and z are positive real numbers, then the minimum possible value of (x + y + z) is

A.24
B.96
C.48
D.36
Algebra/Quadratic Equations/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
3   2 64 3log y. z log y log x 4 log log 8 log 512   ο€½   2 2 3log y. z log ( y) 2log x 4 39 log 2 3log 3log   ο€½   2 2 log y. z log ( y) log x 4 3 log 2 3log 3log   ο€½  log (x) +     log y log y. Z  = 3 Γ— 4 log 2 log (xyz) = log 212  xyz = 212 From minimum x + y + z; x = y = 2 or xyz is constant x3 = 212 x = 24 = 16  Minimum x + y + z = 48

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QA2025MCQhard

The number of divisors of (26 Γ— 35 Γ— 53 Γ— 72), which are of the form (3r + 1), where r is a non-negative integer, is

A.24
B.36
C.42
D.56
Arithmetic/Ratio and Proportion/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
3 A number is of the form 3p + 1 if it leaves remainder 1 when divided by 3. Since 35 is divisible by 3, any divisor containing 35 will be divisible by 3. Therefore, we consider only the case when the power of 3 is zero. Even powers of 2: 20, 22, 24, 26 give remainder 1. Even powers of 5: 50, 52 also give remainder 1. So when both powers are even, the remainder is 1 So number of cases = 4 Γ— 2 = 8 Odd power of 2: 21, 23, 25 Odd power of 5: 51, 53 So number of cases = 3 Γ— 2 = 6 Total valid combinations of powers of 2 and 5 are 8 + 6 = 14 Now, powers of 7: 70, 71, 72 all are of the form (3p + 1). So number of cases = 3 Hence, the number of divisors of the required form is 14 Γ— 3 = 42.

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QA2025TITAmedium

The average number of copies of a book sold per day by a shopkeeper is 60 in the initial seven days and 63 in the initial eight days, after the book launch. On the ninth day, she sells 11 copies less than the eighth day, and the average number of copies sold per day from second day to ninth day becomes 66. The number of copies sold on the first day of the book launch is

Arithmetic/Profit and Loss/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
49 Total sales in first 7 days = 7 Γ— 60 = 420 Total sales in first 8 days = 8 Γ— 63 = 504 So, sales on the 8th day = 504 – 420 = 84 Sales on 9th day = 11 less than 8th day οƒž 9th day sales = 84 – 11 = 73 From 2nd day to 9th day = 8 days; Average = 66 οƒžο€ Total sales from day 2 to day 9 = 8 Γ— 66 = 528 Sales from day 2 to day 9 = (Total of first 8 days + 9th day) – 1st day οƒž 528 = (504 + 73) – 1st day οƒž 1st day = 577 – 528 = 49.

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QA2025TITAeasy

Suppose a, b, c are three distinct natural numbers, such that 3ac = 8(a + b). Then, the smallest possible value of 3a + 2b + c is

Algebra/Linear Equations/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
12 Given, 3ac = 8(a + b), where a, b, c are distinct natural numbers, and we must minimize 3a + 2b + c. Rearranging the given equation we get, 3ac = 8a + 8b οƒž b = a(3c – 8) /8 For b to be a natural number, a(3c – 8) must be divisible by 8. For a = 2 and c = 4 we get b = 1 and these are the smallest possible distinct values of a, b and c. Also all are natural and distinct: (a, b, c) = (2, 1, 4) Hence, 3a + 2b + c = 6 + 2 + 4 = 12.

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Two tangents drawn from a point P touch a circle with centre O at points Q and R. Points A and B lie on PQ and PR, respectively, such that AB is also a tangent to the same circle. If AOB = 50Β°, then APB, in degrees, equals

Algebra/Linear Equations/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
Q P O A B R a a b b S AOB = 50Β° AOQ =AOS = a BOR = BOS = b QOR = QOA + AOS + SOB + BOR = 2a + 2b = 2 (a + b) Now as given AOB = 50Β° = AOS + SOB = 2(a + b) οœο€ οƒQOR = 100Β° In quadrilateral PQOR, Q and R are right angles. Hence, APB = 180Β° – 100Β° = 80Β°. CAT 2025 Solved Paper (Slot-2) 27

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Let ABCDEF be a regular hexagon and P and Q be the midpoints of AB and CD, respectively. Then, the ratio of the areas of trapezium PBCQ and hexagon ABCDEF is

A.6: 19
B.7: 24
C.5: 24
D.6: 25
Geometry/Triangles/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
3 The diagram of the hexagon can be drawn as follows: B C E F A D Q P O In a regular hexagon area of each of the triangles AOB, BOC, COD, DOE, EOF and FOA is equal to one-sixth of the area of the hexagon. Given that P and Q are mid points of AB and CD, using mid-point theorem, we can say that the area enclosed by the trapezium will be equal to = 1/4 area of AOB + 3/4 area of BOC + 1/4 area of COD = 5/4 area of AOB. Hence, required ratio = 5/4: 6 = 5: 24.

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QA2025MCQmedium

A certain amount of money was divided among Pinu, Meena, Rinu and Seema. Pinu received 20% of the total amount and Meena received 40% of the remaining amount. If Seema received 20% less than Pinu, the ratio of the amounts received by Pinu and Rinu is

A.2: 1
B.8: 5
C.5: 8
D.1: 2
Arithmetic/Ratio and Proportion/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
3 Pinu, Meena, Rinu and Seema Let P + R + M + S = 100   P R M S P 20 5    ο€½ ο€½   4 40 M P R M S 5 100  οƒΆ ο€½    ο‚΄  οƒ·  οƒΈ = 32 S = 80% P = 16 οœο€ R = 100 – (20 + 32 + 16) = 32 οœο€ Ratio of P: R:: 20: 32 5: 8

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QA2025MCQmedium

A mixture of coffee and cocoa, 16% of which is coffee, costs Rs 240 per kg. Another mixture of coffee and cocoa, of which 36% is coffee, costs Rs 320 per kg. If a new mixture of coffee and cocoa costs Rs. 376 per kg, then the quantity, in kg, of coffee in 10 kg of this new mixture is

A.4
B.5
C.2.5
D.6
Arithmetic/Mixtures and Alligation/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
2 Let the cost of 1 kg coffee be Rs.C and that of 1 kg cocoa be Rs.D. From mixture 1: 0.16C + 0.84D = 240 …(1) From mixture 2: 0.36C + 0.64D = 320 …(2) Subtract (1) from (2) we get, 0.20C – 0.20D = 80 οƒž C – D = 400 From (1): 0.16C + 0.84(C – 400) = 240 οƒž C = Rs.576 and D = Rs.176 Let the fraction of coffee be x. οƒž 576x + 176(1 – x) = 376 οƒž x = 0.5 So, coffee content = 50% Quantity of coffee in 10 kg = 10 Γ— 0.5 = 5 kg.

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A loan of Rs 1000 is fully repaid by two installments of Rs 530 and Rs 594, paid at the end of first and second year, respectively. If the interest is compounded annually, then the rate of interest, in percentage, is

A.10
B.8
C.11
D.9
Arithmetic/Simple Interest Compound Interest/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
4 Let the annual rate of interest = r% Since interest is compounded annually, the total value of the installments equals the loan amount. 530/(1 + r) + 594/(1 + r)2 = 1000 οƒž 530(1 + r) + 594 = 1000(1 + r2 + 2r) οƒž 530r + 1124 = 1000 + 1000r2 + 2000r οƒž 1000r2 + 1470r – 124 = 0 οƒž r = 0.08 or –1.55 We discard the negative value and take r = 0.08 Hence, rate = 8%

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QA2025TITAhard

If m and n are integers such that (m + 2n)(2m + n) = 27, then the maximum possible value of 2m – 3n is

Arithmetic/Profit and Loss/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
17 Given (m + 2n)(2m + n) = 27 where m and n are integers. Let (m + 2n) = a and (2m + n) = b So n = (2a – b)/3 and m = (2b – a)/3 Also we know that, ab = 27 Possible values of (a, b) are {(1, 27), (3, 9), (9, 3), (27, 1), (–1, –27), (–3, –9), (–9, –3), (–27, –1)} The only pairs that give integer values for m and n are (3, 9), (9, 3), (–3, –9) and (–9, –3). The values of (2m – 3n) that are obtained from the respective pairs of (a, b) are 13, –17, –13 and 17. Hence, the maximum possible value of (2m – 3n) is 17.

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Rita and Sneha can row a boat at 5 km/h and 6 km/h in still water, respectively. In a river flowing with a constant velocity, Sneha takes 48 minutes more to row 14 km upstream than to row the same distance downstream. If Rita starts from a certain location in the river, and returns downstream to the same location, taking a total of 100 minutes, then the total distance, in km, Rita will cover is 13

Arithmetic/Time Speed Distance/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
s r s r 14 14 48 V V V V 60 ο€­ ο€½ ο€­  V5 = 6km/hr Vr = r (Speed of river) 14 14 4 6 r 6 r 5 ο€­ ο€½ ο€­  1 1 2 6 r 6 r 35 ο€­ ο€½ ο€­  2 2r 2 35 36 r ο€½ ο€­ οƒžr = 1, –36  ο€½ ο€½ ο€­  D D 100 5 5 r 5 r 60 3 D D 5 4 6 3  ο€½ ο€½ 5D 5 12 3  D = 4 km οƒž D + D = what distance = 20 Total distance of saved = 8 km

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QA2025MCQeasy

Let an be the nth term of a decreasing infinite geometric progression. If a1 + a2 + a3 = 52 and a1a2 + a2a3 + a3a1 = 624, then the sum of this geometric progression is

A.57
B.60
C.63
D.54
Algebra/Progressions/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
4 a1 = a a2 = ar a3 = ar2  a + ar + ar2 = 52  a(1 + r + r2) = 52  (A) And a1a2 + a2a3 + a3a1 = 624 a. ar + ar. ar2 + ar2. a = 624 ar2 (1 + r2 + r) = 624  (B)   ο€½ ο€½ ο€½  4 2 2 B a (r)(1 r r ) 624 12 A 52 a(1 r r ) 28 CAT 2025 Solved Paper (Slot-2)  ar = 12 οƒž a 12 r ο€½ From (A)   2 12 1 r r 52 r  ο€½ 1 + r + r2 13r 3 ο€½ r2 + 1 10r 3 ο€½ or 1 10 1 r 3 r 3 3  ο€½ ο€½   r = 3 or 1 3 It is a decreasing GP so we take r = 1/3.  a Γ— 1 3 = 12 οƒžο€ a = 36. Sum of GP a 36 1 1 r 1 3 ο€½ ο€½ ο€­ ο€­ = 54

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If a, b, c and d are integers such that their sum is 46, then minimum possible value of (a – b)2 + (a – c)2 + (a – d)2 is

Algebra/Linear Equations/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
2 a + b + c + d = 46 To find min (a – b)2 + (a – c)2 + (a – d)2 If all are equal, minimum will be 0. But 46 is not divisible by 4. So take a = 11, b = 11, c = 12, d = 12 οƒž Min value = 0 + 1 + 1 = 2.

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The sum of digits of the number (625)65 Γ— (128)36, is

Number System/Digits/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
25 N = (625)65 Γ— (128)36 N = (54)65 Γ— (27)36 = 5260 Γ— 2252  N = (10)252 Γ— (58) N = (390625) Γ— 1025 Sum of digits = 3 + 9 + 0 + 6 + 2 + 5 = 25

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An item with a cost price of Rs. 1650 is sold at a certain discount on a fixed marked price to earn a profit of 20% on the cost price. If the discount was doubled, the profit would have been Rs. 110. The rate of discount, in percentage, at which the profit percentage would be equal to the rate of discount, is nearest to

A.12
B.18
C.16
D.14
Arithmetic/Profit and Loss/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
4 Given Cost Price = Rs.1,650 and Profit = 20% of 1650 = Rs.330 Selling Price = 1650 + 330 = Rs.1,980 Let the original discount be d%. 1980 = MP(1 – d/100) …(1) According to the question, if the discount is doubled (i.e. 2d%), profit becomes Rs.110. New Selling Price = 1650 + 110 = Rs.1,760 1760 = MP(1 – 2d/100) …(2) From equation (1) and (2) we get, 1760/1980 = (100 – 2d)/(100 – d) οƒž 800 - 8d = 900 – 18d οƒž 10d = 100 οƒž d = 10% From equation (1), we get, MP = 1980/0.9 = Rs. 2,200 Let new discount = x% Now the profit percentage has to be equal to the discount percentage. Selling price at x% discount = 2200(1 – x/100) Profit percentage = (SP – 1650)/1650 Γ— 100 = (2200 – 22x – 1650)/1650 Γ— 100 οƒž (550 – 22x)/1650 Γ— 100 = x οƒž 165x = 5500 – 220x οƒž 385x = 5500 οƒž x = 5500/385 = 14.286% Hence, the correct answer is 14%.

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The equations 3x2 – 5x + p = 0 and 2x2 – 2x + q = 0 have one common root. The sum of the other roots of these two equations is

A.8 3 p q 3 2 ο€­ 
B.2 2 2p q 3 3 ο€­ 
C.2 3 p q 3 2 ο€­ 
D.8 1 p q 3 3  
Algebra/Quadratic Equations/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
1 Given equations 3x2 – 5x + p = 0 …(1) 2x2 – 2x + q = 0 …(2) Let the common root be . In equation (1) Let the other root be   +  = 5/3 οƒžο€ ο’ = 5/3 –  and  = p/3 οƒžο€ ο‘(5/3 – ) = p/3 οƒž 5 – 32 = p …(3) In equation (2) Let the other root be   +  = 2/2 = 1 οƒžο€ ο§ = 1 –  and  = q/2 οƒžο€ ο‘(1 – ) = q/2 οƒž 2 – 22 = q …(4) Now  +  = 5/3 –  + 1 –  = 8/3 – 2 From (3) and (4) we get, 2 = (2p – 3q)/2 Hence,  +  = 8/3 – (2p – 3q)/2 = 8/3 – p + 3q/2.

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The ratio of expenditures of Lakshmi and Meenakshi is 2: 3, and the ratio of income of Lakshmi to expenditure of Meenakshi is 6: 7. If excess of income over expenditure is saved by Lakshmi and Meenakshi, and the ratio of their savings is 4: 9, then the ratio of their incomes is 14

A.5: 6
B.3: 5
C.2: 1
D.7: 8
Arithmetic/Ratio and Proportion/data/extracted_text/2025/Slot_2/FULL/CAT_2025_Slot_2_FULL.txt
2 Given: Expenditure ratio of Lakshmi: Meenakshi = 2: 3. Let Lakshmi’s expenditure = 2x and Meenakshi’s expenditure = 3x Given: Income of Lakshmi: Expenditure of Meenakshi = 6: 7 οƒž Income of Lakshmi = 6/7 Γ— (3x) = 18x/7 Now, Savings = Income – Expenditure Lakshmi’s savings = 18x/7 – 2x = 4x/7 Let Meenakshi’s income = y; Meenakshi’s savings = y – 3x Given: Savings of Lakshmi: Meenakshi = 4: 9 οƒž (4x/7): (y – 3x) = 4: 9 οƒž y = 30x/7 Lakshmi’s income =18x/7; Meenakshi’s income = 30x/7 Ratio of incomes = 18x/7: 30x/7 = 3: 5.