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Arithmetic/Time & Work

Question

[Arithmetic -- Time & Work, Hard, TITA]

Working alone, AA and BB can complete a certain piece of work in 20 days and 30 days respectively. They are assigned to work together every day, except that AA takes leave on every 5th day (i.e.\ on days 5,10,15,5, 10, 15, \dots); on such days only BB works. Starting on Day 1, the smallest positive integer NN such that the work is completely finished by the end of day NN is ____.

Answer

N=14N = 14.

Detailed solution

[Work with leave schedule]

Daily rates: A=120, B=130A = \tfrac{1}{20},\ B = \tfrac{1}{30}. Joint rate (no leave) =112= \tfrac{1}{12}. On leave days only BB: rate 130\tfrac{1}{30}.

Cumulative work at end of each day (in units of 160\tfrac{1}{60}):

$

Day1234567891011121314Cum.510152022273237424449545964\begin{array}{c|cccccccccccccc} \text{Day} & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 & 11 & 12 & 13 & 14 \text{Cum.} & 5 & 10 & 15 & 20 & 22 & 27 & 32 & 37 & 42 & 44 & 49 & 54 & 59 & 64 \end{array}

$

(Each non-leave day adds 55; leave days 5,105, 10 add 22.) The total work corresponds to 6060. The cumulative crosses 6060 during Day 14. Hence the work is completely finished by the end of Day 14. Answer: N=14N = 14.

Why CAT-level: The trap is to compute average daily rate over a 5-day block, miss the residual, and undercount.