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PEAMCQModerate

2022 PEA Q3

In month 1: pX=2,pY=3p_X = 2, p_Y = 3. Consumer AA chose (3,8)(3,8), consumer BB chose (6,6)(6,6). In month 2: pX=3,pY=2p_X = 3, p_Y = 2. Consumer AA chose (8,3)(8,3), consumer BB chose (4,9)(4,9). Which statement is correct?

Reveal answer and solution

Answer

D

Solution

  1. 1

    Consumer A: Bundle a1=(3,8)a_1 = (3,8), a2=(8,3)a_2 = (8,3).

  2. 2
    Month 1 budget: p1a1=2(3)+3(8)=30,p1a2=2(8)+3(3)=25<30.Month 2 budget: p2a2=3(8)+2(3)=30,p2a1=3(3)+2(8)=25<30.\begin{aligned} \text{Month 1 budget:}\ & p^1 \cdot a_1 = 2(3)+3(8) = 30,\quad p^1 \cdot a_2 = 2(8)+3(3) = 25 < 30. \\ \text{Month 2 budget:}\ & p^2 \cdot a_2 = 3(8)+2(3) = 30,\quad p^2 \cdot a_1 = 3(3)+2(8) = 25 < 30. \end{aligned}
  3. 3

    Both bundles are directly revealed preferred to each other, violating WARP.

  4. 4

    Consumer B: Bundle b1=(6,6)b_1 = (6,6), b2=(4,9)b_2 = (4,9).

  5. 5
    p1b1=12+18=30,p1b2=8+27=35>30.p2b2=12+18=30,p2b1=18+12=3030.\begin{aligned} p^1 \cdot b_1 &= 12+18 = 30, & p^1 \cdot b_2 &= 8+27 = 35 > 30. \\ p^2 \cdot b_2 &= 12+18 = 30, & p^2 \cdot b_1 &= 18+12 = 30 \le 30. \end{aligned}
  6. 6

    In month 2, b1b_1 was affordable and b2b_2 was chosen, so b2b1b_2 \succsim b_1.

  7. 7

    In month 1, b2b_2 was not affordable, so no contradictory revelation exists. Consumer BB

  8. 8

    satisfies WARP.

  9. 9

    Hence consumer BB satisfies WARP but AA does not.

Answer structure / marking notes

Watch for the case where bundles cost exactly the budget at the other period --- equality with the chosen bundle's value still counts as ``affordable''.

Content note

Imported from public/resources/isi/msqe/solutions/pea/2022/ISI_MSQE_PEA_2022_Solutions.tex. Question wording is retained from the available local TeX source; incomplete option blocks or ambiguous source status are flagged for review.