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2025 PEA Q6

Y=Amin{K,L}Y = A\min\{K,L\}, A>0A > 0. With W=Y/LW=\partial Y/\partial L and R=Y/KR = \partial Y/\partial K:

Reveal answer and solution

Answer

D

Solution

  1. 1

    With k=K/Lk = K/L:

  2. 2

    \begin{itemize}[leftmargin=*]

  3. 3
    • If K<LK < L (i.e.\ k<1k<1), Y=AKY = AK, so Y/K=A\partial Y/\partial K = A and Y/L=0\partial Y/\partial L = 0. Hence R=AR = A, W=0W = 0.
  4. 4
    • If K>LK > L (i.e.\ k>1k>1), Y=ALY = AL, so Y/K=0\partial Y/\partial K = 0 and Y/L=A\partial Y/\partial L = A. Hence R=0R = 0, W=AW = A.
  5. 5

    \end{itemize}

  6. 6

    RR and WW are equal only at the kink k=1k=1 (and even there the derivatives are not well defined). In no full region are RR and WW equal.

Answer structure / marking notes

The Leontief function is not differentiable at K=LK=L; option (A) is a tempting but wrong symmetry answer.

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Content note

Imported from public/resources/isi/msqe/solutions/pea/2025/ISI_MSQE_PEA_2025_Solutions.tex. Question wording is retained from the available local TeX source; incomplete option blocks or ambiguous source status are flagged for review.