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PEAMCQHard

2025 PEA Q25

MC=25MC = 25. 55 high'' people have $MB_H = 100 - 0.5Q$, $10$ low'' people have MBL=500.25QMB_L = 50 - 0.25Q. Max number of trees voluntarily provided with cost-sharing?

Reveal answer and solution

Answer

D

Solution

  1. 1

    Aggregate (vertical) marginal benefit is

  2. 2
    MB=5(1000.5Q)+10(500.25Q)(while both groups have positive MB). \sum MB = 5(100 - 0.5Q) + 10(50 - 0.25 Q) \quad \text{(while both groups have positive } MB).
  3. 3

    But each group's MBMB becomes zero at:

  4. 4

    \begin{itemize}[leftmargin=*]

  5. 5
    • MBH=0Q=200MB_H = 0 \Rightarrow Q = 200,
  6. 6
    • MBL=0Q=200MB_L = 0 \Rightarrow Q = 200.
  7. 7

    \end{itemize}

  8. 8

    Both groups have positive MBMB for Q<200Q < 200. So,

  9. 9
    MB=5002.5Q+5002.5Q=10005Q. \sum MB = 500 - 2.5 Q + 500 - 2.5 Q = 1000 - 5 Q.
  10. 10

    Setting MB=MC\sum MB = MC (Samuelson condition for socially optimal QQ):

  11. 11
    10005Q=25    Q=195. 1000 - 5 Q = 25 \;\Longrightarrow\; Q = 195.

Answer structure / marking notes

For public goods, sum WTPs vertically, not horizontally. Both groups' WTP is positive at Q<200Q < 200.

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Content note

Imported from public/resources/isi/msqe/solutions/pea/2025/ISI_MSQE_PEA_2025_Solutions.tex. Question wording is retained from the available local TeX source; incomplete option blocks or ambiguous source status are flagged for review.