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2026 PEA Q30

A two-period consumer maximises

U(C1,C2)=logC1+11+ρlogC2,ρ>0, U(C_1, C_2) = \log C_1 + \tfrac{1}{1+\rho}\log C_2, \qquad \rho > 0,

subject to C1+S=wC_1 + S = w and C2=(1+r)SC_2 = (1+r) S, with w,r>0w, r > 0. If ww rises by 1%1\% and rr falls by 1%1\%, then SS

Reveal answer and solution

Answer

B

Solution

  1. 1

    Substitute C2=(1+r)(wC1)C_2 = (1+r)(w - C_1) into UU and differentiate w.r.t.\ C1C_1:

  2. 2
    1C111+ρ1+rC2(1+r)11+r=1C11(1+ρ)C2(1+r)11+r(1+r). \frac{1}{C_1} - \frac{1}{1+\rho}\cdot \frac{1+r}{C_2}\cdot(1+r)\cdot\frac{1}{1+r} = \frac{1}{C_1} - \frac{1}{(1+\rho) C_2}\,(1+r)\cdot\frac{1}{1+r} \cdot (1+r).
  3. 3

    A cleaner derivation: the Euler equation C2C1=1+r1+ρ\dfrac{C_2}{C_1} = \dfrac{1+r}{1+\rho}, combined with the lifetime budget constraint C1+C21+r=wC_1 + \dfrac{C_2}{1+r} = w, gives

  4. 4
    C1+11+r1+r1+ρC1  =  wC1 ⁣(1+11+ρ)=wC1=(1+ρ)w2+ρ. C_1 + \frac{1}{1+r}\cdot \frac{1+r}{1+\rho}\,C_1 \;=\; w \quad\Longrightarrow\quad C_1\!\left(1 + \frac{1}{1+\rho}\right) = w \quad\Longrightarrow\quad C_1 = \frac{(1+\rho)\,w}{2+\rho}.
  5. 5

    Therefore

  6. 6
    S=wC1=w ⁣(11+ρ2+ρ)=w2+ρ. S = w - C_1 = w\!\left(1 - \frac{1+\rho}{2+\rho}\right) = \frac{w}{2+\rho}.
  7. 7

    This is the well-known log-utility result: *saving is proportional to wage

  8. 8

    and independent of rr* (income and substitution effects of an interest-rate

  9. 9

    change cancel exactly under log preferences).

  10. 10

    Since SS depends only on ww (not on rr):

  11. 11

    \begin{itemize}

  12. 12
    • A 1%1\% rise in ww raises SS by exactly 1%1\%.
  13. 13
    • A 1%1\% fall in rr leaves SS unchanged.
  14. 14

    \end{itemize}

  15. 15

    Therefore SS rises by exactly 1%1\%.

Answer structure / marking notes

Under log utility the income and substitution effects of a change in rr on saving cancel out exactly; this is a special property of log preferences.

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Review Flags

Question 18. As transcribed (with uA=xA+yu_A = x_A + y, uB=2xB+yu_B = 2x_B + y and production constraint y+m(xA+xB)=1y + m(x_A + x_B) = 1), the Samuelson condition yields m=2/3m = 2/3, which is not among the printed options {4/5,4/7,4/9,4/11}\{4/5,\,4/7,\,4/9,\,4/11\}. The problem statement (likely the utility functions or the production technology in the underlying source) should be verified before finalising the option choice.

All other questions are flagged as either Verified or Draft (see the Answer-Key Summary at the front of this booklet).

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\begin{center} \textit{End of PEA Solutions --- ISI MSQE 2026, prepared for Statstrive.} \end{center}

Content note

Imported from public/resources/isi/msqe/solutions/pea/2026/ISI_MSQE_PEA_2026_Solutions.tex. Question wording is retained from the available local TeX source; incomplete option blocks or ambiguous source status are flagged for review.